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Pachacha [2.7K]
3 years ago
14

A long bar slides on two contact points and is in motion with velocity ν. A steady, uniform, magnetic field B is present. The in

duced current through resistor R is:
Physics
1 answer:
fomenos3 years ago
5 0

Answer:

The induced current in the resistor is I = BLv/R

Explanation:

The induced emf ε in the long bar of length, L in a magnetic field of strength, B moving with a velocity, v is given by

ε = BLv.

Now, the current I in the resistor is given by

I = ε/R where ε = induced emf in circuit and R = resistance of resistor.

So, the current I = ε/R.

substituting the value of ε the induced emf, we have

I = ε/R

I = BLv/R

So, the induced current through the resistor is given by I = BLv/R

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A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this p
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Answer:

Acceleration of proton will be a=0.67\times 10^{11}m/sec^2

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