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erastovalidia [21]
3 years ago
6

A fisherman fishing from a pier observes that the float on his line bobs up and down, taking 2.4 s to move from its highest to i

ts lowest point. He also estimates that the distance between adjacent wave crests is 48 m. What is the speed of the waves going past the pier?
(A) 20 m/s

(B) 1.0 m/s

(C) 10 m/s

(D) 5.0 m/s

(E) 115 m/s
Physics
1 answer:
mars1129 [50]3 years ago
4 0

Answer:

(c) 10m/s

Explanation:

to find the speed of the waves you can use the following formula:

v=\frac{\lambda}{T}

λ: wavelength of the wave

T: period

the wavelength is the distance between crests = 48m

the period is the time of a complete oscillation of the wave. In this case you have that the float takes 2.4 s to go from its highest to the lowest point. The period will be twice that time:

T = 2(2.4s)=4.8s

by replacing you obtain:

v=\frac{48m}{4.8s}=10\frac{m}{s}

the answer is (c) 10m/s

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A 1200 kg car starts from rest and travels 100m in a time of 10 seconds . A) what is the acceleration of the car? B) what force
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Given:
Mass (m) = 1200 kg
Distance (s) = 100 m
Time (t) = 10 seconds
Now,
velocity (v) =  \frac{distance}{time}

                         = \frac{100~ m}{10~seconds}

                         = 10 m/s
<span><u>Note that this one is the final velocity.</u></span><u />
We also know that, 
initial velocity (u) = 0 m/s .......<span> because the car starts from rest.
</span>Now,
acceleration (a)= \frac{change~in~velocity}{time}

                               = \frac{v-u}{t}

                               = \frac{10-0}{10}

                               = 1 m/s²
Now,
Force (F) = mass (m) * acceleration (a)
                = 1200 kg * 1 m/s²
                = 1200 kg.m/s²
                = 1200 N
Now,
Work Done (W) = Force (F) * displacement (s) ....<span>note that displacement is                                                                                                      same as distance.
</span><span>                          = 1200 N * 100 m
</span>                          = 120000 N.m
                          = 120000 J
Now,
Power (P) = \frac{Work~done(W)}{time(t)}

                 = \frac{120000~J}{10s}

                 = 12000 J/s
                 = 12000 watt
SO,
 A) The acceleration of the car is 1 m/s².
 B) 1200 Newton (N) force must have acted on the car.
 C) The velocity of the car after 10 seconds is 10 m/s.
 D) 120000 Joule (J) work was done on the car.
 E) The engine produced a minimum power of 12000 watt.
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4 years ago
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