Answer:
3 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 32 ft/s²
174 feet from the ground is 174-14 = 160 ft from the launch area
When the arrow will reach the 160 ft point while returning the initial velocity becomes equal to the final velocity which means the time taken to come down also becomes equal.
Hence, the arrow will be 1.5+1.5 = 3 seconds above a height of 174 ft from the ground.
Answer:
Explanation:
As we know that tension force in the string will be equal to the centripetal force on the string
so we will have
now we have
now we have
now when string length is 0.896 m and its speed is 71.5 m/s then we will have
Correct answer is:
<span>B. Subtract the initial velocity from the final velocity and divide the result by the time
In fact, the formula to calculate the acceleration is
</span>
<span>where vf is the final velocity, vi the initial velocity, and t the time.</span>
It is an real machine because if efficiency is below100% it is real machine but if efficiency is 100% it is an ideal machine
Answer:
330Ns
Explanation:
Given parameters:
Mass of the box = 5kg
Initial velocity = 0m/s
Force applied = 15N
Time = 22s
Unknown:
Impulse = ?
Final momentum = ?
Solution:
The impulse of the box can be determined using the expression below:
Impulse = Force x time
Impulse = 15 x 22 = 330Ns
The final momentum is the same as this impulse
The impulse and the final momentum is 330Ns