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Misha Larkins [42]
3 years ago
8

Filament bulbs give off lots of __________ that transfers wasted energy to the surroundings. What word completes the sentence?​

Physics
1 answer:
Anika [276]3 years ago
6 0

Answer:

filament bulbs give off lots of metal filament that transfers wasted energy to the surrounding.

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Who is the scientist who developed the planetary model of the atom
Maurinko [17]

Neils Bohr

In 1913, Neils Bohr, a student of Rutherford 's, developed a new model of the atom. He proposed that electrons are arranged in concentric circular orbits around the nucleus. This model is patterned on the solar system and is known as the planetary model.

7 0
3 years ago
PLEASE HELP I HAVE NO IDEA HOW TO COMPLETE THIS AND ITS DUE TONIGHT
tankabanditka [31]

Answer:

Lo tienes que hacer con una tabla dde conversiones :)

Explanation:

7 0
3 years ago
A certain CD has a playing time of 74.0 minutes. When the music starts, the CD is rotating at an angular speed of 480 revolution
Rashid [163]

Answer: 0.00636\ rad/s^2

Explanation:

Given

CD has a playing time of t=74\ min\ or\  74\times 60\ s

Initial angular speed of CD is 480\ rpm

Final angular speed of DC is 210\ rpm

Angular speed, when rpm is given

\omega =\dfrac{2\pi N}{60}

\omega_i=\dfrac{2\pi \times 480}{60}\\\\\Rightarrow \omega_i=16\pi \ rad/s

Final speed

\Rightarrow \omega_f=\dfrac{2\pi \times 210}{60}\\\\\Rightarrow \omega_f=7\pi \ rad/s

Using equation of angular motion

\Rightarrow \omega_f=\omega_i+\alpha t

Insert the values

\Rightarrow 7\pi =16\pi +\alpha \times 74\times 60\\\Rightarrow -9\pi =\alpha \cdot (4440)\\\\\Rightarrow \alpha=-\dfrac{9\pi}{4440}\\\\\Rightarrow \alpha=-0.00636\ rad/s^2

Magnitude of angular acceleration is 0.00636\ rad/s^2

3 0
3 years ago
The instantaneous speed of a particle moving along one straight line is v(t) = ate−6t, where the speed v is measured in meters p
beks73 [17]

Answer:

v_max = (1/6)e^-1 a

Explanation:

You have the following equation for the instantaneous speed of a particle:

v(t)=ate^{-6t}   (1)

To find the expression for the maximum speed in terms of the acceleration "a", you first derivative v(t) respect to time t:

\frac{dv(t)}{dt}=\frac{d}{dt}[ate^{-6t}]=a[(1)e^{-6t}+t(e^{-6t}(-6))]  (2)

where you have use the derivative of a product.

Next, you equal the expression (2) to zero in order to calculate t:

a[(1)e^{-6t}-6te^{-6t}]=0\\\\1-6t=0\\\\t=\frac{1}{6}

For t = 1/6 you obtain the maximum speed.

Then, you replace that value of t in the expression (1):

v_{max}=a(\frac{1}{6})e^{-6(\frac{1}{6})}=\frac{e^{-1}}{6}a

hence, the maximum speed is v_max = ((1/6)e^-1)a

5 0
3 years ago
The latitude of the city of Arlington is about 32.7357°. Calculate the following: (a) The angular speed of the Earth. (b) The li
julia-pushkina [17]

Answer:

Explanation:

a ) The earth rotates by 2π radian in 24 x 60 x 60 s

so angular speed ( w )  = 2π / (24 x 60 x 60)  = 7.268 x  10⁻⁵ rad / s

b ) Linear speed of city of Arlington ( v )  = w r = w R Cosλ where R is radius of the earth and λ is latitude .

v = 7.268 x 10⁻⁵ x  6.371 x 10⁶ cos 32.7357

389.5 m /s

acceleration = w² r = w² R Cos 32.7357

= (7.268 x 10⁻⁵ )² x 6.371 x 10⁶ x cos 32.7357

=283.08 x 10⁻⁴ m/s²

c) velocity ratio =

w r /w R =

R cos 32.73/ R  

= Cos 32.73

= 0.84 .

6 0
4 years ago
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