Answer: - 452.088joule
Explanation:
Given the following :
Mass of water = 12g
Change in temperature(Dt) = (11 - 20)°C = - 9°C
Specific heats capacity of water(c) = 4.186j/g°C
Q = mcDt
Where Q = quantity of heat
Q = 12g × 4.186j/g°C × - 9°C
Q = - 452.088joule
Density = mass/volume
= 4300/10000
= 0.43 g/mL.
Therefore density of liquid propane is 0.43 g/mL.
Hope this helps!
Answer:
True
Explanation:
If two partners don't communicate they'll grow apart and it may lead to one or the other cheating.
