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Serjik [45]
3 years ago
13

If Rojelio starts out at rest, and in 10 s speeds up to 50 m/s, what is his acceleration?

Physics
1 answer:
vovikov84 [41]3 years ago
3 0

Answer:

C) - 5m/s^2

Explanation:

U=0(started from rest)

V=50m/s

T=10s

Acceleration =v-u/t

=50-0/10

=5m/s^2

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Answer:

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Explanation:

The vector is resolved in terms of the vertical and horizontal components. Let's look each of these separately.

The vector 4.40 is directed East. This automatically becomes a horizontal component.

But we know that there is a vector 3.40 North West. The angle the vector makes with the horizontal is 61⁰.

Resolving the vectors should yield the horizontal and vertical components:

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The first component is 4.40 m

The second one is derived by resolving 3.40 to the horizontal like this 3.40 × - cos 61⁰ = -1.648 m

Adding the horizontal component gives 4.40 m + ( -1.648 m) = 2.752 m

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Resolve 3.40 with the angle 61⁰ like this: vertical comp = 3.41 × sin 61

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The magnitude is given by √[(2.98)²+ (2.752)²] = 4.056 m Ans

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