Answer:
About 10.2 g Li₃N.
Explanation:
We are given the reaction:

And we want to determine the amount of Li₃N that can be formed from 6.07 g of Li and an excess of nitrogen.
To convert from g Li to g Li₃N, we can: (1) convert from g Li to mol Li, (2) mol Li to mol Li₃N, and (3) mol Li₃N to g Li₃N.
- The molecular weight of Li is 6.94 g/mol.
- From the equation, six moles of Li yields two moles of Li₃N.
- And the molecular weight of Li₃N is 34.83 g/mol as shown below.
Molecular weight of Li₃N:

This yields three ratios:

From the initial value, multiply:

In conclusion, 10.2 g of Li₃N is formed from 6.07 g of Li and an excess of nitrogen.