<span>Answer:
A 0.04403 g sample of gas occupies 10.0-mL at 289.0 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% C and 74.695% Cl. What is the molecular formula of the compound?
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Seems like I did a problem very similar to this--this must be the "B" test. But the halogen was different.
25.305% C/12 = 2.108
74.695% Cl/35.5 = 2.104
So the empirical formula would be CH. However, there are many compounds which fit this bill, so we have to use the gas data. (And I made, in the previous problem, the simplifying assumption that 289C and 1.10 atm would offset each other, so I'll do that, too.)
0.044 grams/10 ml = x/22.4 liters
0.044g/0.010 liters = x/22.4 liters
22.4 liters/0.010 liters = 2240 (ratio)
2240 x .044 = 98.56 (actual atomic weight)
CCl = 35.5+12 or 47.5, so two of those is 95 grams/mole.
This is sufficiient to distinguish C2CL2, (dichloroacetylene)
from C6CL6 (hexachlorobenzene) which would
mass 3 times as much.</span>
Answer:
Yes
Explanation:
Is this a question or what?
Yes, Sharpies contain volatile solvents—and when inhaled these solvents can produce a "high." The effects of inhalants (including Sharpies) can be similar to those of alcohol and include slurred speech, lack of coordination, euphoria, and dizziness.
Answer:
to provide energy to the body and helps u grow stonger
Explanation:
<span>The molar mass of the compound is 36.355 g/mol. This is calculated by knowing that 1 mol of gas fills 22.4 L of volume, so 1.623 g/L = X g/mol * 1/22.4 mol/L -> 1.623 g/L * 22.4 L/mol = X g/mol -> 36.355 g/mol = X g/mol</span>
