The equation 3y = x + 1 would graph a line parallel to 3y = x + 5 ⇒ 1st
Step-by-step explanation:
Parallel lines have same slopes and different y-intercepts
To find which equation would graph a line parallel to 3y = x + 5
1. Put the equation in the form of y = mx + c
2. m is the slope of the line and c is the y-intercept
3. Look for the equation which has the same values of m and different
values of c
∵ 3y = x + 5
- Divide each term of the equation by 3 to put the equation in the
form of y = mx + c
∴ y =
x + 
∴ m = 
∴ c = 
The first answer:
∵ 3y = x + 1
- Divide each term of the equation by 3
∴ y =
x + 
∴ m = 
∴ c = 
∵ The two equations have same slope m = 
∵ The two equations have different y-intercepts c = 
and c = 
∴ 3y = x + 5 and 3y = x + 1 represent two parallel lines
The equation 3y = x + 1 would graph a line parallel to 3y = x + 5
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No, because element b has 2 correspondents.
10186.28
And that’s how you do it
<u>Answer:</u> The ratio that represents the cosine of ∠T is 
<u>Step-by-step explanation:</u>
We are given:
UV = 56 units
VT = 33 units
UT = 65 units
∠V = 90°
Cosine of an angle is equal to the ratio of base and the hypotenuse of the triangle. ΔTUV is drawn in the image below.

Base of the triangle is UV and the hypotenuse of the triangle is TU
Putting values in above equation, we get:

Hence, the ratio that represents the cosine of ∠T is 
Answer:
s = -2
Step-by-step explanation:
2(s+2)=4(s+2)
2s + 4 = 4s + 8
2s - 4s = 8 - 4
-2s + 4
s = -2