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Nonamiya [84]
3 years ago
5

Help asap please thank you

Physics
1 answer:
Romashka [77]3 years ago
5 0
I would say 8 since 11-3 is 8 so it took that much seconds to accelerate. Sorry if I’m wrong
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A 36,287 kg truck has a momentum of 907,175 kg • . What is the truck’s velocity?
Snowcat [4.5K]
By definition,
Momentum = Mass * Velocity

Let v =  the velocity of the truck, m/s
The mass of the truck is 36,287 kg.
The momentum is 907,175 (kg-m)/s.

Therefore
907,175 (kg-m)/s = (36287 kg)*(v m/s)
v = 907175/36287 = 25 m/s

Answer: 25 m/s

7 0
4 years ago
Read 2 more answers
Two blocks of masses 8 kg and 4.3 kg are placed on a horizontal, frictionless surface. A light spring is attached to one of them
oee [108]

Answer:

The velocity of other mass is 3.60 m/s.

Explanation:

Given that,

Mass of first block = 8 kg

mass of second block = 4.3 kg

Speed = 6.7 m/s

We need to calculate the speed of first mass

Using conservation of momentum

(m_{1}+m_{2})u=m_{1}v_{1}+m_{2}v_{2}

where, m₁ =mass of first block

m₂ =mass of second block

m₁ =mass of first block

v₂ =speed of second block

Put the value into the formula

8+4.3\times0=8\times v_{1}+4.3\times6.7

v_{1}=\dfrac{-4.3\times6.7}{8}

v_{1}=-3.60\ m/s

Negative sign represent the opposite direction of initial value.

Hence, The velocity of other mass is 3.60 m/s.

3 0
3 years ago
A(n) __________ exhibits sedimentary layers that are parallel to each other above and below an erosive surface.
wlad13 [49]
<span>disconformity is the correct answer
</span> 
7 0
3 years ago
It has been suggested that a heat engine could be developed that made use of the fact that the temperature several hundred meter
lesantik [10]

Answer:

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Explanation:

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now we will have

W = Q_1 - Q_2

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\eta = 1 - \frac{Q_2}{Q_1}

now we know that

\frac{Q_2}{Q_1} = \frac{T_2}{T_1}

so we have

\eta = 1 - \frac{T_2}{T_1}

\eta = 1 - \frac{273+6}{273+22}

\eta = 0.054

so efficiency is 5.4%

8 0
3 years ago
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Schach [20]

Answer:

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