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adelina 88 [10]
3 years ago
13

A(n) __________ exhibits sedimentary layers that are parallel to each other above and below an erosive surface.

Physics
1 answer:
wlad13 [49]3 years ago
7 0
<span>disconformity is the correct answer
</span> 
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A merry-go-round is rotating at an angular speed of 0.2 radians/s. Its motor falls off and it rotates freely. A technician jumps
I am Lyosha [343]

Answer:

  I₁ =1250  kg.m²

Explanation:

Given that

Angular speed of Merry ,ω₁= 0.2 rad/s

Angular speed of technician ,ω₂= 0.04 rad/s

Moment of the inertia of the technician ,I₂= 5000 kg.m²

Lets assume that

Moment of the inertia of merry with respected to the ground=I₁

There is no any external torque ,that is why angular momentum of the system will be conserve.

Now by conserving angular momentum

I₁ ω₁=(I₁+I₂)ω₂

I₁  x 0.2  = (I₁ +5000 ) x 0.04

I₁ (0.2-0.04) = 5000 x 0.04

I_1=\dfrac{5000\times 0.04}{0.2-0.04}

I₁ =1250  kg.m²

5 0
3 years ago
The distance between a charge and the source of an electric field changes from 3 mm to 6 mm. as a result of the change, the elec
STatiana [176]

The electric potential energy of the charge is reduced because it decreases with increase in the distance between charges.

<h3>What is electric potential energy?</h3>

Electric potential energy can be defined as the energy needed to move a charge against an electric field.

It is calculated using the formula;

U = Kq1 q2 ÷ r

Where Q = electric potential energy

k = Coulombs constant

q1 and q2 = charges

r = distance of separation

Electric potential energy is inversely proportional to the distance of separation of the charges.

If the distance of the charges changes from 3mm to 6mm, then the electric potential energy of the charges is reduced because it decreases with increase in the distance of the charges.

Therefore, the electric potential energy of the charge is reduced because it decreases with increase in the distance between charges.

Learn more about electric potential energy here:

brainly.com/question/14812976

#SPJ1

4 0
2 years ago
A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V?What is the total energy stores in the
Rama09 [41]

1) 1.11\cdot 10^{-7} J

The capacitance of a parallel-plate capacitor is given by:

C=\frac{\epsilon_0 A}{d}

where

\epsilon_0 is the vacuum permittivity

A is the area of each plate

d is the distance between the plates

Here, the radius of each plate is

r=\frac{2.0 cm}{2}=1.0 cm=0.01 m

so the area is

A=\pi r^2 = \pi (0.01 m)^2=3.14\cdot 10^{-4} m^2

While the separation between the plates is

d=0.50 mm=5\cdot 10^{-4} m

So the capacitance is

C=\frac{(8.85\cdot 10^{-12} F/m)(3.14\cdot 10^{-4} m^2)}{5\cdot 10^{-4} m}=5.56\cdot 10^{-12} F

And now we can find the energy stored,which is given by:

U=\frac{1}{2}CV^2=\frac{1}{2}(5.56\cdot 10^{-12} F/m)(200 V)^2=1.11\cdot 10^{-7} J

2) 0.71 J/m^3

The magnitude of the electric field is given by

E=\frac{V}{d}=\frac{200 V}{5\cdot 10^{-4} m}=4\cdot 10^5 V/m

and the energy density of the electric field is given by

u=\frac{1}{2}\epsilon_0 E^2

and using

E=4\cdot 10^5 V/m, we find

u=\frac{1}{2}(8.85\cdot 10^{-12} F/m)(4\cdot 10^5 V/m)^2=0.71 J/m^3

7 0
4 years ago
What is a gas squeezed into a smaller space
Dmitriy789 [7]
Its called compressing the gas
3 0
3 years ago
.) List the molecules of elements in the sample of air. Give the
Ksivusya [100]

Answer:

Explanation: N2 Nitrogen, O2 Oxygen, Ar does not form molecules

8 0
3 years ago
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