The answer is D. 27
54 divided by 2 is 27
Answer:
52
Step-by-step explanation:
answer is in photo above
4374÷9=486 you could use a calculator or write down the working
Answer: Choice B
- vertex = (3, -4)
- y intercept = (0, 5)
- x intercepts = (1, 0) and (5, 0)
- axis of symmetry: x = 3
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Explanation:
The vertex is the lowest point for parabolas that open upward like this. The lowest point is (3, -4). If the parabola is flipped upside down, then the vertex would be the highest point.
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The y intercept is where the graph crosses the y axis. For any function, it will have at most one y intercept (some don't have any at all but the most you can have is 1 y intercept). The graph crosses the vertical y axis at (0,5). We can say in short "the y intercept is 5". The y intercept always occurs when x = 0.
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On the flip side, the x intercept always occurs when y = 0. This is where the graph crosses or touches the x axis. We have two such locations of (1,0) and (5,0). In short, we could say "the x intercepts are 1 and 5". The term "root" is another word we could use in place for "x intercept". Unlike the y intercept, we can have as many x intercepts as we want.
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The axis of symmetry is the vertical line through the parabola. It is the x coordinate of the vertex. So it's not a coincidence that the vertex is at (3,-4) and the axis of symmetry is x = 3, with those '3's repeated twice.
Answer:
A quadratic function generally does not have an inverse except on a restricted domain. If the domain of the <em>original</em> function is restricted to x ≥ 0, then the inverse function is ...
Step-by-step explanation:
Start by interchanging x and "y", then solve for y.
y = 5x² +4 . . . . . . given
x = 5y² +4 . . . . . . with x and y interchanged
x -4 = 5y² . . . . . . subtract 4
(x -4)/5 = y² . . . . . divide by 5
√((x -4)/5) = y . . . take the square root . . . . x ≥ 4, y ≥ 0
Then, ...
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The graph shows the original f(x) and the "inverse", called f1(x). Note that it is only a reflection across y=x of the right half of the original function. That is, the inverse only exists for the original function when its domain is restricted to x ≥ 0. (The domain of the inverse function is x ≥ 4.)