For question number 1, the answer is B.
For question nunber 2, the answer is D.
1. If we cross YyLl (heterozygous parent with dominant traits) with yyll (homozygous parent with recessive traits)
P: YyLl x yyll
F1 generation: YyLl: 400 Yyll: 100 yyLl: 100 yyll: 400
Recombinant offspring are those children whose genes contain a non-parental allele combination (neither allele group is directly inherited from either parent). This happens when genes are located on the same chromosome but are so far apart from one another so that their alleles get crossed over during meiosis. In this case, Yyll and yyLl are the recombinant.
2. Calculation of distance between Y and L.
The numbers of the two recombinant types is 200 (100 Yyll + 100 yyLl) and 800 parental offspring.
Total number of offspring is 1000.
So: 200/1000*100=20 map units.
There is 20 percent recombinant offspring frequency.
Answer:
The 200kg man would have more potential energy.
Explanation:
because of his mass compared to the 50 kg little girl.
Answer: C. he believes returning to get back will inspire others to make changes and do the same
Explanation:
