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Delvig [45]
3 years ago
7

Bruno Mars has $108 and is spending

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

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The water inside a right cylinder tank is 6 inches above the bottom part of the tank of radius 1 feet and length 2 feet. Find th
ASHA 777 [7]

Answer:

<h2>864π in³</h2>

Step-by-step explanation:

Volume of the water is equivalent to the volume of a cylinder = πr²h where;

r is the radius of the cylindrical tank

h is the height of the water

Given parameters

radius of the cylindrical tank r = 1feet = 12 inches

height of the water inside the tank = 6inches

Volume of the water = πr²h

Volume of the water  = π(12)²*6

Volume of the water  = π*144*6

Volume of the water  = 864π in³

<em></em>

<em>Hence the volume of the water is 864π in³</em>

8 0
3 years ago
Read 2 more answers
If f(x) = x2 + 2x – 1, find f(1).<br> Answer:
Alina [70]

Answer:

f(1)= (1)^2+ 2(1) -1

= 2

7 0
3 years ago
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Can someone help me i cant understand with work
Masja [62]

Answer:

Right now it would be

-40

Since desend means down add -20 to -40

-40+(-20)=-60

         or

-40-20=-60

Then is goes up 35, which is positive

-60+35=-25

Therefore, the answer is -25

Hope this helps

Answer by

<em>Fishylikeswater</em>

<em></em>

3 0
3 years ago
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What would you have to do to change 10 cubic feet into cubic inches?
Alina [70]

A. Divide by 46,656

B. Multiply by 1,728

C. Divide by 1,728

D. Multiply by 46,656

THE ANSWER IS B MULTIPLY BY 1,728


5 0
3 years ago
Find the smallest zero of f(x+5)
podryga [215]

ANSWER

1. k=13

2. x=-10

EXPLANATION

The given function is

f(x) =  {x}^{2}   + 3x  - 10

To find f(x+5), plug in (x+5) wherever you see x.

This implies that:

f(x) =  {(x + 5)}^{2}   + 3(x + 5) - 10

Expand:

f(x) =   {x}^{2}    + 10x + 25+ 3x + 15- 10

Simplify to obtain

f(x) =   {x}^{2}    + 13x + 30

We now compare with,

f(x) =   {x}^{2}    + kx + 30

This implies that:

k = 13

To find the smallest zero of f(x+5), we equate the function to zero and solve for x.

{x}^{2}    + 13x + 30 = 0

{x}^{2}   + 10x + 3x + 30 = 0

x(x + 10) + 3(x + 10) = 0

(x + 3)(x + 10) = 0

x =  - 10 \: or \: x =  - 3

The smallest zero is -10.

7 0
3 years ago
Read 2 more answers
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