Vector trigonometry can be used for this problem. Since the horizontal component is 12 meters per second, this is technically the hypotenuse (actual initial velocity) multiplied to cosine of 40 degrees. Therefore, to find the hypotenuse, we must divide 12 by cosine 40degrees. cos(40)= 0.766, and 12/0.766 = approximately 15.664, therefore our answer is (3) 15.7 m/s
As you approach the surface of the sphere very closely, the electric field should resemble more and more the electric field from an infinite plane of charge.
If you check Gauss's law (recalling that the field in the conductor is zero) you will see that if the surface charge density is σ=Q/4πR2, then indeed the field at the surface is σ/ϵ0 as in the infinite charge of plane case.
Such a field is constant, the field lines are parallel and non-diverging, and the infinities associated with the field due to point charge do not arise.
Explanation:
Answer:
75 Newtons.
Explanation:
From Newton's second law of motion,
F = m(v-u)/t................... Equation 1
Where F = force exerted by the ball on the bat, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball, t = time
Given: m = 0.6 kilogram, u = 0 meter per seconds (at rest), v = 25 meters per seconds, t = 0.2 seconds.
Substitute into equation 1
F = 0.6(25-0)/0.2
F = 3(25)
F = 75 Newton.
Hence the magnitude of the average force exerted by the ball on the bat = 75 Newtons.
Answer:
Increase
Explanation:
because it's increasing up.
Answer:
Because they are moving to fast for Earth's gravity to pull it down.
