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3 years ago

11

Explain why the roller coaster’s potential energy is greater at point 1 than at point 4.

2 answers:

Virty [35]3 years ago

3 0

Potential energy is directly related to the height of an object. Point 1 is higher than point 4, so the potential energy is greater at point 1.

spayn [35]3 years ago

3 0

The most probable answer would be Point 1 is higher than Point 4.

Potential gravitational energy is computed by the formula:

PEgrav =mgh

m = mass

g = acceleration due to gravity (this is a constant value of 9.8m/s²)

h = height

The roller coaster of course, no matter where in the track it is would have the same mass (Unless someone falls off -_-) Pull of gravity is the same as well.

So the only factor that would affect it is the height. So if the height goes up, the potential energy goes up too. If the height goes down, then the potential energy goes down too.

Hopefully you'll come up with the right answer with this. v(0-0)v

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4vir4ik [10]

Answer:

The fraction fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for 3.0 time constants is

$k = 0.903$

Explanation:

From the question we are told that

The time constant $\tau = 3$

The potential across the capacitor can be mathematically represented as

$V = V_o (1 - e^{- \tau})$

Where $V_o$ is the voltage of the capacitor when it is fully charged

So at $\tau = 3$

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$V = 0.950213 V_o$

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In this equation the energy stored is directly proportional to the the square of the potential across the capacitor

Now since capacitance is constant at $\tau = 3$

The energy stored can be evaluated at as

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$V^2 = 0.903 V_o ^2$

Hence the fraction of the energy stored in an initially uncharged capacitor is

$k = 0.903$

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3 years ago

A dog walks 12 meters to the east and then 16 meters back to the west for this motion what is the distance moved What is the mag

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The distance is 28 meters, and the displacement is -4.

For the distance it would be 12 + 16 = 28.

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An internal explosion breaks an object, initially at rest, into two pieces: A and B. Piece A has 1.9 times the mass of piece B.

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<h3>What is the relation between the masses of A and B?</h3>

Let mass of piece A = Ma

Mass of piece B = Mb

Velocities of pieces A and B are Va and Vb respectively.
As per conservation of momentum,

Ma×Va = Mb×Vb

Here, Ma=1.9Mb

So, 1.9Mb × Va = Mb×Vb

=> 1.9Va = Vb

<h3>What are the kinetic energy of piece A and B?</h3>

Expression of kinetic energy of piece A = 1/2 × Ma × Va²
Kinetic energy of piece B = 1/2 × Mb × Vb²
Total kinetic energy= 7900J

=>1/2 × Ma × Va² + 1/2 × Mb × Vb² = 7900

=> 1/2 × Ma × Va² + 1/2 × (Ma/1.9) × (1.9Va)² = 7900

=> 1/2 × Ma × Va² ×(1+1.9) = 7900 j

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Thus, we can conclude that the kinetic energy of piece A and B are 2724 Joule and 5176 Joule respectively.

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