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Tems11 [23]
3 years ago
10

In water, HNO3 produces H+ ions. Which is the name for HNO3 in an aqueous solution?

Chemistry
2 answers:
ozzi3 years ago
7 0
Nitric acid<span> is the chemical name for HNO3(</span>aq<span>). The </span>compound<span> is composed of </span>hydrogen<span>, </span>nitrogen<span> and </span>oxygen<span>. </span>
Alborosie3 years ago
4 0

<u>Answer:</u> It is named as nitric acid in aqueous solution.

<u>Explanation:</u>

HNO_3 is an acid because it releases hydrogen ions when dissolved in water. The chemical equation for the ionization of HNO_3 follows:

HNO_3(aq.)\rightarrow H^+(aq.)+NO_3^-(aq.)

When an element is present in the higher oxidation state in a compound, a suffix '-ic' is added at the end.

When an element is present in the lowest oxidation state in a compound, a suffix '-ous' is added at the end.

Nitrogen shows oxidation state of +5 and +3. In the given compound, nitrogen is present in +5 oxidation state. Thus, in the naming of the compound, a suffix '-ic' is added.

Hence, the given compound is named as nitric acid in aqueous solution.

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Express the van der Waals equation of state as a virial expansion in powers of 1/Vm and obtain expressions for B and C in terms
nirvana33 [79]

Answer:

PV_{m} = RT[1 + (b-\frac{a}{RT})\frac{1}{V_{m} } + \frac{b^{2} }{V^{2} _{m} } + ...]

B = b -a/RT

C = b^2

a = 1.263 atm*L^2/mol^2

b = 0.03464 L/mol

Explanation:

In the given question, we need to express the van der Waals equation of state as a virial expansion in powers of 1/Vm and obtain expressions for B and C in terms of the parameters a and b. Therefore:

Using the van deer Waals equation of state:

P = \frac{RT}{V_{m}-b } - \frac{a}{V_{m} ^{2} }

With further simplification, we have:

P = RT[\frac{1}{V_{m}-b } - \frac{a}{RTV_{m} ^{2} }]

Then, we have:

P = \frac{RT}{V_{m} } [\frac{1}{1-\frac{b}{V_{m} } } - \frac{a}{RTV_{m} }]

Therefore,

PV_{m} = RT[(1-\frac{b}{V_{m} }) ^{-1} - \frac{a}{RTV_{m} }]

Using the expansion:

(1-x)^{-1} = 1 + x + x^{2} + ....

Therefore,

PV_{m} = RT[1+\frac{b}{V_{m} }+\frac{b^{2} }{V_{m} ^{2} } + ... -\frac{a}{RTV_{m} }]

Thus:

PV_{m} = RT[1 + (b-\frac{a}{RT})\frac{1}{V_{m} } + \frac{b^{2} }{V^{2} _{m} } + ...]           equation (1)

Using the virial equation of state:

P = RT[\frac{1}{V_{m} }+ \frac{B}{V_{m} ^{2}}+\frac{C}{V_{m} ^{3} }+ ...]

Thus:

PV_{m} = RT[1+ \frac{B}{V_{m} }+ \frac{C}{V_{m} ^{2} } + ...]     equation (2)

Comparing equations (1) and (2), we have:

B = b -a/RT

C = b^2

Using the measurements on argon gave B = −21.7 cm3 mol−1 and C = 1200 cm6 mol−2 for the virial coefficients at 273 K.

b = \sqrt{C} = \sqrt{1200} = 34.64[tex]cm^{3}/mol[/tex] = 0.03464 L/mol

a = (b-B)*RT = (34.64+21.7)*(1L/1000cm^3)*(0.0821)*(273) = 1.263 atm*L^2/mol^2

3 0
2 years ago
Which of the following particles combine to form molecules?
solniwko [45]

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Explanation:

7 0
3 years ago
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natima [27]

Answer:

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Explanation:

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3 years ago
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sineoko [7]
A(n )amide is an organic compound in which a carbonyl group is bonded to a nitrogen atom. This is <span>usually regarded as derivatives of carboxylic acids in which the hydroxyl group has been replaced by an amine or ammonia.</span>
3 0
3 years ago
Read 2 more answers
For the reaction:
Sophie [7]

Hey there!

For SN1 mechanism; the activation barrier is the C-I bond energy which is broken in the first step of the reaction.

The activation barrier is : 56 kcal/ mol = 5.6 kcal/ mole ( nearest 0.1)

6 0
3 years ago
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