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Tems11 [23]
3 years ago
10

In water, HNO3 produces H+ ions. Which is the name for HNO3 in an aqueous solution?

Chemistry
2 answers:
ozzi3 years ago
7 0
Nitric acid<span> is the chemical name for HNO3(</span>aq<span>). The </span>compound<span> is composed of </span>hydrogen<span>, </span>nitrogen<span> and </span>oxygen<span>. </span>
Alborosie3 years ago
4 0

<u>Answer:</u> It is named as nitric acid in aqueous solution.

<u>Explanation:</u>

HNO_3 is an acid because it releases hydrogen ions when dissolved in water. The chemical equation for the ionization of HNO_3 follows:

HNO_3(aq.)\rightarrow H^+(aq.)+NO_3^-(aq.)

When an element is present in the higher oxidation state in a compound, a suffix '-ic' is added at the end.

When an element is present in the lowest oxidation state in a compound, a suffix '-ous' is added at the end.

Nitrogen shows oxidation state of +5 and +3. In the given compound, nitrogen is present in +5 oxidation state. Thus, in the naming of the compound, a suffix '-ic' is added.

Hence, the given compound is named as nitric acid in aqueous solution.

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Find the [h3o ] in a sauvignon blanc with a ph of 3.24.
KengaRu [80]
Hello!

The H₃O⁺ concentration can be found using the definition of pH and clearing the equation for [H₃O⁺]. The solution has a pH lower than 7, so the Sauvignon Blanc is acid. The calculation for [H₃O⁺] is shown below:

pH=-log [H_3O^{+}]

[H_3O^{+}]= 10^{-pH}=10^{-3,24}=0,00058M

So, the concentration of H₃O⁺ in a Sauvignon Blanc with a pH of 3,24 is 0,00058 M

Have a nice day!
7 0
2 years ago
Which one(s) below right about valence electrons?
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2 years ago
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A pure compound is composed of?<br><br>pls Answer this directly<br>​
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7 0
2 years ago
Complete the equation for the ionization of water by drawing the conjugate acid and conjugate base. Include lone pairs of electr
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5 0
3 years ago
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So I saw this question: If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + Na
Nataly_w [17]

mass of PbI₂ = 27.6606 g

<h3>Further explanation</h3>

Given

Pb(NO₃)₂ + NaI → PbI₂ + NaNO₃

28.0 grams of Pb(NO₃)₂ react with 18.0 grams of NaI

Required

mass of PbI₂

Solution

Balanced equation

Pb(NO₃)₂ + 2NaI → PbI₂ + 2NaNO₃

The principle of a balanced reaction is the number of atoms in the reactants = the number of atoms in the product

mol Pb(NO₃)₂ :

= 28 : 331,2 g/mol

= 0.0845

mol NaI :

= 18 : 149,89 g/mol

= 0.12

Limiting reactant : mol : coefficient

Pb(NO₃)₂ : 0.0845 : 1 = 0.0845

NaI : 0.12 : 2 = 0.06

NaI limiting reactant (smaller ratio)

mol PbI₂ based on NaI

= 1/2 x 0.12 = 0.06

Mass PbI₂ :

= 0.06 x 461,01 g/mol

= 27.6606 g

4 0
3 years ago
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