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Oduvanchick [21]
3 years ago
15

Ammonium sulfate, an important chemical fertilizer, can be prepared by the reaction of ammonia with sulfuric acid according to t

he following balanced equation:
2 NH3(g) + H2SO4(aq) → (NH4)2SO4(aq)

If a reaction vessel has 3.29 L of NH3 at 31.5°C and 22.7 atm, how many grams of H2SO4 are needed to completely react with it?

_________________ g H2SO4. Do NOT enter unit. Report your final answer with 3 SFs.
Chemistry
1 answer:
sweet-ann [11.9K]3 years ago
3 0

Answer:

147 grams

Explanation:

<u>We are given: </u>

Pressure (P) = 22.7 atm

Temperature (T) = 304.5 K

Volume (V) = 3.29 L

<u>Solving for the number of moles of Ammonia:</u>

From the Ideal Gas Equation:

PV = nRT

replacing the variables

(22.7)(3.29) = n (0.082)(304.5)           [R = 0.082 L atm / mol K]

n = 3 moles (approx)

<u>Number of moles of Sulphuric Acid required:</u>

We are given the balanced equation:

2 NH3(g) + H2SO4(aq) → (NH4)2SO4(aq)

we can see that for 2 moles of Ammonia, we will need 1 mole of Sulphuric acid

So, we can say that we need half the number of moles of sulphuric acid as compared to Ammonia

Hence, We will need half the number of moles of Ammonia

Number of moles of Sulphuric acid required = 1/2 * Moles of Ammonia

Moles of Sulphuric Acid = 1/2 * 3

Moles of Sulphuric acid = 3/2 moles

<u>Mass of Sulphuric Acid needed:</u>

We know that the molar mass of Sulphuric acid is 98 grams/mol

We know that the mass of a given number of moles of a compound is the number of moles multiplied by the molar mass

Mass of Sulphuric Acid = Number of moles * Molar mass

Mass of Sulphuric Acid = 1.5 * 98

Mass of Sulphuric Acid = 147 grams

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Answer:

Molecular formula = P₄O₆

Explanation:

P(s)         +        O₂(g)------------------------------------⇒ PₓOₙ (g)

10g                     (17.77-10)g                                    17.77g

10g                        7.77g                                          17.77g  (gramme ratio)

The molecular mass of Phosphorus  (P) = 31g/mole

The molecular mass of Oxygen atom (O) = 16g/mole

Mole ratio is given by:

P              :             O

10/31                    7.77/16

0.3226       :         0.4856                Mole ratio---------------------------- (1)

Divide (1)  through by 0.3226

 1                 :        1.5-------------------------------------------- (2)

From  (2), the empirical formula for Phosphorus oxide :

Empirical formula = P₁O₁.₅

                               =  PO₁.₅

The molecular formula can be calculated from below:

Since the molecular formula is a multiple of the empirical formula we have

Molecular formula = (PO₁.₅)ₙ----------------------------------- (3)

Since we are given the molecular mass of the oxide formed, we have:

(PO₁.₅)ₙ = 220-----------------------------(4)

[31 + (16 x 1.5)] x n = 220

[31 + 24]n = 220

55n =220

n = 4

Substituting into (3), we have :

Molecular formula = (PO₁.₅)₄

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A supernova reaches its peak brightness a few days after it first occurred, during which time it may outshine an entire galaxy of stars. The dead star then continues to shine intensely for several weeks before gradually fading from view, according to "Supernova."

The material from a supernova eventually disperses throughout interstellar space. The oldest stars almost exclusively consisted of hydrogen and helium, with oxygen and the rest of the heavy elements in the universe later coming from supernova explosions, according to "Cosmic Collisions: The Hubble Atlas of Merging Galaxies," (Springer, 2009).

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In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an ex
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The question is incomplete. The complete question is :

In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an explanation that tells how much NaOH needs to be added to a beaker of HCl to cause the color to change. Your explanation can be something like: The color change will occur when [some amount] of NaOH is added because the color change occurs when [some condition]. The goal for your explanation is that it describes the outcome of this example, but can also be used to predict the outcome of other examples of this phenomenon. Here's an example explanation: The color of the solution will change when 40 ml of NaOH is added to a beaker of HCl because the color always changes when 40ml of base is added. Although this explanation works for this example, it probably won't work in examples where the flask contains a different amount of HCl, such as 30ml. Try to make an explanation that accurately predicts the outcome of other versions of this phenomenon.

Solution :

Consider the equation of the reaction between NaOH and $HCl$

  NaOH (aq) + HCl (aq) → NaCl(aq) + $H_2O (l)$

The above equation tells us that $1 \text{mole}$ of $NaOH$ reacts with $1 \text{mole}$ of $HCl$.

So at the equivalence point, the moles of NaOH added = moles of $HCl$present.

If the volume of the $HCl$ taken = $V_1$ mL and the conc. of $HCl$ = $M_1$  mole/L

The volume of NaOH added up to the color change = $V_2 \text{  and conc of NaOH = M}_2$ mole/L

Moles of $HCl$ taken = $V_1 \ mL \times M_1 \ mol/100 \ mL = V_2M_2 \times 10^{-3}$  moles.

The color change will occur when the moles of NaOH added is equal to the moles of $HCl$ taken.

Thus when $V_1 M_1 \times 10^{-3} = V_2M_2 \times 10^{-3}$

or   when    $V_1M_1 = V_2M_2$

or $V_2=\frac{V_1M_1}{M_2}$  mL of NaOH added, we observe the color change.

Where $V_1, M_1$ are the volume and molarity of the $HCl$ taken.

$M_2$ is the molarity of NaOH added.

When both the NaOH and $HCl$ are of the same concentrations, i.e. if $M_1=M_2$, then $V_2=V_1$

Or the 40 mL of $HCl$ will need 40 mL of NaOH for a color change and

30 mL of $HCl$ would need 30 mL of NaOH for the color change (provided the concentration $M_1=M_2$)

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