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3 years ago

Given the reaction:

Chemistry

2 answers:

Nadusha1986 [10]3 years ago

8 0

Your answer will be B

Archy [21]3 years ago

7 0

The answer is 12. Al4C3 + 12 H2O = 4 Al(OH)3 + 3 CH4

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G the ksp of calcium hydroxide, ca(oh)2, is 5.02 × 10-6. calculate the molar solubility of this compound.

g100num [7]

When calcium hydroxide dissolves, it dissociates into Ca(OH)2 = Ca2+ and 2OH- Let's assign the variable X for the solubility of Ca2+ and OH I.e Ca2+ = X and 2OH- = 2X Then Ksp = [Ca2+][OH-]^2 So we have (X) (2X)^2 = 5.02 * 10^(-6) 4X^3 = 5.02 * 10 ^(-6) X^3 = 5.02 * 10^(-6) / 4 X^3 = 0.003110 X = 0.1459

7 0

3 years ago

Need some help with this Chem Question :)

Kruka [31]

Answer:

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

Explanation:

The activity series helps us to easily define whether or not a reaction will occur.

Elements at the top of the activity series are highly reactive and will always displace those at the bottom of the series in any reaction.

With the above information in mind, let us answer the questions given above.

Ag + NaNO₃ —> Na + AgNO₃

The above reaction will not occur because Na is higher than Ag in the activity series. Thus, Ag cannot displace Na from solution.

Pb + Mg(NO₃)₂ —> Pb(NO₃)₂ + Mg

The above reaction will not occur because Mg is higher than Pb in the activity series. Thus, Pb cannot displace Mg from solution.

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

The above reaction will occur because Mg is higher than Fe in the activity series. Thus, Mg will displace Fe from solution.

Cu + Mg(NO₃)₂ —> Cu(NO₃)₂ + Mg

The above reaction will not occur because Mg is higher than Cu in the activity series. Thus, Cu cannot displace Mg from solution.

From the above illustration, only

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

Will occur.

5 0

2 years ago

Does a fish's scales shred as the fish grows larger

tia_tia [17]

Answer: No.

Explanation: Unless a disaster happens to their environment their scales will only grow.

7 0

2 years ago

a glass container was initially charged with 1.50 mol of a gas sample at 3.75 atm and 21.7C. some of the gas was release as the

butalik [34]

Answer:

0.39 mol

Explanation:

Considering the ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

At same volume, for two situations, the above equation can be written as:-

$\frac {{n_1}\times {T_1}}{P_1}=\frac {{n_2}\times {T_2}}{P_2}$

Given ,

n₁ = 1.50 mol

n₂ = ?

P₁ = 3.75 atm

P₂ = 0.998 atm

T₁ = 21.7 ºC

T₂ = 28.1 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (21.7 + 273.15) K = 294.85 K

T₂ = (28.1 + 273.15) K = 301.25 K

Using above equation as:

$\frac{{n_1}\times {T_1}}{P_1}=\frac{{n_2}\times {T_2}}{P_2}$

$\frac{{1.50\ mol}\times {294.85\ K }}{3.75\ atm}=\frac{{n_2}\times {301.25\ K }}{0.998\ atm}$

$n_2=\frac{{1.50}\times {294.85}\times 0.998}{3.75\times 301.25}\ mol$

Solving for n₂ , we get:

n₂ = 0.39 mol

7 0

3 years ago

Use the dropdown to create a unbalanced diagram with the dog using Applied Force pulling to the right.

Ber [7]

Is there an image with this question

7 0

3 years ago