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2 years ago

Mary is buying tickets for a movie.

Mathematics

1 answer:

Anastasy [175]2 years ago

3 0

adult ticket = 10

child ticket = 4

Step-by-step explanation:

for example…

adult ticket = x
child ticket = y

so that we get a system of equations

9x + 5y = 110…Equation 1

x + y = 14…Equation 2

solve the system of equations, this time I will use the Elimination and Substitution method

9x + 5y = 110

x + y = 14 (multiplied by 5)

↓↓↓↓↓↓↓

9x + 5y = 110

5x + 5y = 70

___________ _

4x = 40

x = 10

to find value of y subtitute x to one of Equation. for example from second Equation…

x + y = 14

10 + y = 14

y = 14 - 10

y = 4

∴ So, the number of each ticket was she bought is 10 adult ticket and 4 child ticket.

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katovenus [111]

Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

One sample has a mean of and a second sample has a mean of . The two samples are combined into a single set of scores. What is t

Murrr4er [49]

Answer:

a) For this case we can use the definition of weighted average given by:

$M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}$

And if we replace the values given we have:

$M = \frac{8*4 + 16*4}{4+4}= 12$

b) $M = \frac{8*3 + 16*5}{3+5}= 13$

c) $M = \frac{8*5 + 16*3}{5+3}= 11$

Step-by-step explanation:

Assuming the following question: "One sample has a mean of M=8 and a second sample has a mean of M=16 . The two samples are combined into a single set of scores.

a) What is the mean for the combined set if both of the original samples have n=4 scores "

For this case we can use the definition of weighted average given by:

$M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}$

And if we replace the values given we have:

$M = \frac{8*4 + 16*4}{4+4}= 12$

b) what is the mean for the combined set if the first sample has n=3 and the second sample has n=5

Using the definition we have:

$M = \frac{8*3 + 16*5}{3+5}= 13$

c) what is the mean for the combined set if the first sample has n=5 and the second sample has n=3

Using the definition we have:

$M = \frac{8*5 + 16*3}{5+3}= 11$

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2 years ago