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Alchen [17]
3 years ago
8

Question 3 (0.2 points)

Chemistry
1 answer:
bulgar [2K]3 years ago
6 0
True, the bigger the object the more thermal energy it can hold.
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Which is the correct equation for: iron + sulfur → iron (III) sulfide
shepuryov [24]
The correct equation for: iron + sulfur -> iron (III) sulfide is D
8 0
3 years ago
What is 0.0006250 L in scientific notation
inn [45]
6.250 * 10 to the negative 3

5 0
3 years ago
Read 2 more answers
What is the mass of 2.50 × 1025 molecules of sugar (c12h22o11)?
allochka39001 [22]
To determine the mass of the sugar molecules given, we  need to convert the given value into moles by using the a constant. <span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. Then, by using the molar mass of sugar, we can convert from moles to grams. Molar mass of sugar is 342.3 g/mol. We do as follows:

</span><span>2.50 × 10^25 molecules of sugar ( 1 mol / 6.022x10^23 g ) ( 342.3 g / 1 mol) = 14210.40 grams of sugar present</span>

3 0
4 years ago
NEED HELP PLEASE ASAP
Elenna [48]

Answer:

Sugar aka Glucose

Explanation:

Cellular respiration is reverse photosynthesis! Using that knowledge we know that plants release oxygen and glucose (sugar) which is what is needed for cellular respiration to occur!

Hope this helped! Stay safe and good luck!

7 0
4 years ago
What concentration of NO−3NO3− results when 897 mL897 mL of 0.497 M NaNO30.497 M NaNO3 is mixed with 813 mL813 mL of 0.341 M Ca(
ZanzabumX [31]

Answer:

Explanation:

NaNO₃  = Na⁺  + NO₃⁻¹

.497 M                 .497 M

moles of NO₃⁻¹ = .897 x .497 = .4458 moles

Ca( NO₃)₂  = Ca + 2 NO₃⁻¹

.341 M                    2 x .341 M = .682 M

moles of NO₃⁻¹ = .813 x .682 = .5544 moles

Total moles =  .4458 moles  +  .5544 moles

= 1.0002 moles

volume of solution = 897 + 813 = 1710 mL

= 1.710 L

concentration of nitrate ion = 1.0002 / 1.710 M

= .585 M

8 0
4 years ago
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