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atroni [7]
3 years ago
13

Nêu và giải thích hiện tượng trong các thí nghiệm sau

Chemistry
2 answers:
Grace [21]3 years ago
7 0

Answer:

fhdne fjdjdjfnnxnd ddkkddkjxf

posledela3 years ago
7 0

Answer:

Nói tiếng anh po

Explanation:

uhmm A. tôi nghĩ

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Describe all of the van der Waals forces that exist between molecules of water.
faust18 [17]

Explanation:

The van der Waals' forces are the forces that exist between the millions of separate water molecules, and not between the hydrogen and oxygen atoms in the case of water. Dipole-Dipole forces are one of van der Waals' three forces. ... For example, HCl comprised of the atom Hydrogen and Chlorine is polar.

5 0
3 years ago
Using the chemical equation in Question 1 above, if 42.6 g of H2 reacts in excess nitrogen gas and the actual yield of NH3 was 2
S_A_V [24]

Answer:

The answer to your question is:  82.9 %

Explanation:

Data

H2 = 42.6 g

NH3 = 200 g

percent yield = ?

Reaction

                  3H2   +   N2   ⇒       2NH3

Process

                 6 g of H ---------------   34 g of N

                42.6 g     -------------      x

                 x = 241.4 g of NH3

percent yield = 200 / 241.4 x 100

                     = 82.9 %          

8 0
3 years ago
Read 2 more answers
Which role do fungi serve?
zavuch27 [327]

B) Recyclers of energy, as they decompose matter and turn it into energy that can be passed on to other organisms who eat the fungi

3 0
4 years ago
Four hundred kg/h of Steam from a low pressure turbine at 12.5 atm. and 250 C goes into a feed water heater which preheats the w
Nitella [24]

Explanation:

According to the heat relationship,

    Heat given by steam = heat taken by water

Hence,    (mC_{p} \Delta T)_{steam} = (mC_{p} \Delta T)_{water}

where, C_{p} = specific heat

Value of C_{p}_{steam} at 250^{o}C and 12.5 atm is 2.326 kJ/Kg^{o}C.

And, C_{p}_{steam} at 200^{o}C and 12.5 atm is 2.743 kJ/Kg^{o}C.

Therefore, average C_{p}_{steam} = \frac{2.326 kJ/Kg^{o}C + 2.743 kJ/Kg^{o}C}{2}

                                          = 2.5345 kJ/Kg^{o}C

As the given data is as follows.

      m_{steam} = 400 kg/hr, \Delta T_{steam} = 250^{o}C - 200^{o}C = 50^{o}C, m_{water} = 500 kg/hr

            C_{p}_{water} = 4.186 kJ/kg^{o}C

Hence, putting the given values into the above formula as follows.

           (mC_{p} \Delta T)_{steam} = (mC_{p} \Delta T)_{water}

  (400 \times 2.5345 kJ/kg^{o}C \times 50^{o}C)_{steam} = (500 kg \times 4.186 kJ/kg^{o}C \Delta T)_{water}

                \Delta T_{water} = 24.2^{o}C

As we know that, \Delta T_{water} = T_{2} - T_{1}

                             T_{2} - 20^{o}C = 24.2^{o}C

                            T_{2} = 44.2^{o}C

Thus, we can conclude that the new temperature of water is 44.2^{o}C.

3 0
4 years ago
What do the atoms of a metal look like when they are in a body-centered cubic arrangement? A a cube with a ball stuck on each of
Natali [406]
<span>B) a cube with a ball stuck on each of its eight corners and one suspended at its center </span>
4 0
4 years ago
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