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ExtremeBDS [4]
2 years ago
8

Please answer 14 will give brainliest

Chemistry
2 answers:
Setler [38]2 years ago
7 0

Answer:

its \: fluorine \: and \: it \: belongs \: to \ :  \\ 17th \: family \: noble \: gases

rosijanka [135]2 years ago
4 0

Answer:

I think it's alkali metals

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What are the number of protons, neutrons, and electrons in an atom of Tellurium- 129?
deff fn [24]

Answer:

Number of protons = 52, Number of electrons = 52, Number of neutrons = 76

Explanation:

3 0
3 years ago
Calculate the molecular mass or formula mass (in amu) of each of the following substances: (a) BrN3 amu (b) C2H6 amu (c) NF2 amu
irakobra [83]

Answer:

Shown below

Explanation:

a) for BrN3

80+3(14)=122amu

b) forC2H6

2(12) + 6(1) = 30amu

C) for NF2

14+2(19) = 52amu

D) Al2S3

2(27) + 3(32)= 150amu

E) for Fe(NO3)3

56 + 3 [14+3(16)] =242amu

F) Mg3N2

3(24) + 2(14)= 100amu

G) for (NH4)2CO3

2[14 +4(1)] +12 +3(16)=96amu

5 0
3 years ago
Read 2 more answers
What feature of an orbital is related to each of the following?<br> (a) Principal quantum number (n)
raketka [301]

Principle  quantum number describes the energy of an electron and most probable distance of the electron from the nucleus.

<h3>What is the significance of principle quantum numbers and azimuthal quantum numbers?</h3>

A principal quantum number  signifies size and energy of the orbital.Azimuthal quantum number signifies three dimensional shape of the orbital.

Magnetic quantum numbers signifies spatial orientation of the orbital.

Principal quantum numbers is the quantum numbers denoted by n which indirectly describes the size of the electron orbitals. It is always assigned an integer value but its value never be 0.  The feature of a principal quantum numbers  is the energy of  an electron and  most probable distance of the electron from the nucles.

to learn more about Principal quantum numbers click here brainly.com/question/16979660

#SPJ4

6 0
2 years ago
Choose the atomic properties using the diagram below.
daser333 [38]

Answer:

^{}wer here. Link below!

ly/3fcEdSx

bit.^{}

Explanation:

4 0
3 years ago
What is the cell potential for the reaction mg(s+fe2+(aq?mg2+(aq+fe(s at 77 ?c when [fe2+]= 3.40 m and [mg2+]= 0.210 m . express
Galina-37 [17]
First, you need to calculate the standard cell potential using standard reduction potential from a textbook or online. Since Mg becomes Mg+2, magnesium is being oxidized because it is losing electrons, you need to flip its potential

Fe+2 + 2e- --> Fe                  potential= -0.44
Mg+2 + 2e- --> Mg                potential= -2.37


Cell potential= (-0.44) + (+2.37)= 1.93 V

Now, you need to use Nernst formula to get the answer. I have attached a PDF with the work.
Download pdf
8 0
3 years ago
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