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natali 33 [55]
2 years ago
15

Radioactive decay is likely to occur when ... radioactive decay is likely to occur when ... protons break into neutrons and elec

trons. atoms collide with one another. an electron hits the nucleus. an atom has too many neutrons. an atom has too many electrons.
Chemistry
2 answers:
sergey [27]2 years ago
7 0

Answer:

When an atoms has too many neutrons.

Explanation:

When an unstable atom loses energy and charged particles (radiation) through radiation it is a phenomenon called radioactive decay, when a substantial energy is lost the atom becomes stable.There are five types of radioactive decay:

  1. Alpha decay
  2. Beta negative decay
  3. Gamma decay
  4. Beta positive decay
  5. Electron capture

xenn [34]2 years ago
3 0
Radioactivity or radioactive decay is the process that occurs when unstable isotopes or atoms release energy by emitting radiations such as ,gamma radiations, alpha radiations and beta radiations to attain stability. Therefore, in this case decay is likely to occur when a given atom has two many neutrons in its nucleus in order to attain stability.
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The ability of an atom in a molecule to attract electrons is best quantified by the ________.
nevsk [136]

Answer:

b. electronegativity

Explanation:

The ability of an atom in a molecule to attract electrons is best quantified by the _Electronegativity_.

Electronegativity is the ability of an atom to attract a shared pair of electron which is loosely held. Polar molecules often possess such properties. The Halogen group (group 17) is famous for such property because it has the highest electronegativity in periodic table.  

7 0
2 years ago
Bf3 can be octet or not​
makvit [3.9K]

Answer:

(BH3 follows the octet rule by dimerizing, as Hadi Kurniawan AR pointed out.) For H and He, an "octet" = 2 electrons. Boron does prefer to follow the octet rule, in that it likes to form borate compounds such as NaBH4. It also is happy to form compounds with elements with lone pairs.

7 0
3 years ago
Is combining water and powdered drink mix a chemical reaction?
VikaD [51]

Answer:

No, it's a physical reaction.

Explanation:

A chemical change produces new chemical compounds, but combining water and powder is just mixing the powder with the water. It's not a new compound.

I don't know how to really explain, sorry :)

3 0
2 years ago
Select all that apply.
serious [3.7K]
A beta particle is an electron and it has a -1 charge and zero mass.

Beta decay by emitting an electron is called as β⁻ decay. When this happens, a neutron of the element converts into a proton by emitting an electron. Hence, the mass of daughter nucleus is same as parent atom but atomic number/number of protons is higher by 1 than atomic number of parent atom.

In a β⁻ decay, the symbol is used as ₋₁⁰β or ₋₁⁰e.
             -1 is for charge
<span>              0 is for the mass of the particle

</span>
4 0
3 years ago
Read 2 more answers
Please help me like now please
777dan777 [17]

Answer:

1-1) NaHCO3 + CH3COOH --> NaCH3COO + H2O + CO2

1-2) 0.5 mole of CO2

2-1) 2C4H10 + 13O2 --> 8CO2 + 10H2O

2-2) 4 mol CO2

Explanation:

<u>Question 1</u>

NaHCO3 + CH3COOH --> NaCH3COO + H2O + CO2

<em>To balance the equation, count the number of atoms on both sides of the equation</em>

(1 Na, 1+3+1H, 1+1+1C, 3+2Oxygen) --> (1 Na, 1+1+1C, 3+2H, 2+1+2Oxygen)

<em>Combining the pluses will give you the following</em>

(1 Na, 5H, 3C, 5Oxygen) --> (1 Na, 3C, 5H, 5Oxygen)

<em>Both sides are the same, therefore the chemical equation is balanced (originally). </em>

From the equation, we can see that <u>1 mole of NaHCO3</u> produces <u>1 mole of CO2</u>.

So that means <u>0.5 mole of NaHCO3</u> would produce <u>0.5 mole of CO2</u>.

<u>Question 2</u>

C4H10 + O2 --> CO2 + H2O

<em>Again, count the number of atoms on both sides of the equation</em>

(4C, 10H, 2O) --> (1C, 2H, 3O)     <em>This time left does not equal right side</em>

<em>You now need to find </em><u><em>factors </em></u><em>that can make both sides equal. </em>

C4H10 + O2 --> <u>4</u>CO2 + H2O    <em>Now the C is balanced, let's recount </em>

<em>(4C, 10H, 2Oxygen) --> (4C, 8+1Oxygen, 2H)      H&O is still not balanced</em>

C4H10 + O2 --> 4CO2 + <u>5</u>H2O    <em>Now the H is balanced, let's recount</em>

<em>(4C, 10H, 2Oxygen) --> (4C, 8+5Oxygen, 10H)      O is still not balanced</em>

C4H10 + (<u>13/2</u>)O2 --> 4CO2 + 5H2O    <em>Now the O is balanced</em>

<em>(4C, 10H, 13Oxygen) --> (4C, 13Oxygen, 10H)</em>

<em>But because 13/2 is a fraction, we want to eliminate that by multiplying every reactant and product by 2 (the denominator).</em>

<u>2</u>C4H10 + <u>13</u>O2 --> <u>8</u>CO2 + <u>10</u>H2O    Now it's completely balanced!

<em>(8C, 20H, 28Oxygen) --> (8C, 28Oxygen, 20H)     Yayy! It's balanced.</em>

Now, 2 mol C4H10 produces 8 mol CO2.

So 1 mol C4H10 produces 4 mol CO2.

6 0
2 years ago
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