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natali 33 [55]
2 years ago
15

Radioactive decay is likely to occur when ... radioactive decay is likely to occur when ... protons break into neutrons and elec

trons. atoms collide with one another. an electron hits the nucleus. an atom has too many neutrons. an atom has too many electrons.
Chemistry
2 answers:
sergey [27]2 years ago
7 0

Answer:

When an atoms has too many neutrons.

Explanation:

When an unstable atom loses energy and charged particles (radiation) through radiation it is a phenomenon called radioactive decay, when a substantial energy is lost the atom becomes stable.There are five types of radioactive decay:

  1. Alpha decay
  2. Beta negative decay
  3. Gamma decay
  4. Beta positive decay
  5. Electron capture

xenn [34]2 years ago
3 0
Radioactivity or radioactive decay is the process that occurs when unstable isotopes or atoms release energy by emitting radiations such as ,gamma radiations, alpha radiations and beta radiations to attain stability. Therefore, in this case decay is likely to occur when a given atom has two many neutrons in its nucleus in order to attain stability.
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How to write a balanced nuclear equation on how uranium can disintegrate to Actium​
andrey2020 [161]

Answer:

Balancing Nuclear Equations

To balance a nuclear equation, the mass number and atomic numbers of all particles on either side of the arrow must be equal.

Explanation:

follows:

6

3

Li

+

2

1

H

→

4

2

He

+

?

To balance the equation above for mass, charge, and mass number, the second nucleus on the right side must have atomic number 2 and mass number 4; it is therefore also helium-4. The complete equation therefore reads:

6

3

Li

+

2

1

H

→

4

2

He

+

4

2

He

Or, more simply:

6

3

Li

+

2

1

H

→

2

4

2

He

image

Lithium-6 plus deuterium gives two helium-4s.: The visual representation of the equation we used as an example.

Compact

5 0
2 years ago
One of the few xenon compounds that form is cesium xenon heptafluoride (CsXeF7). How many moles of CsXeF7 can be produced from t
larisa [96]
The balanced chemical equation is written as:

<span>CsF(s) + XeF6(s) ------> CsXeF7(s)

We are given the amount of </span>cesium fluoride and <span>xenon hexafluoride used for the reaction. We need to determine first the limiting reactant to proceed with the calculation. From the equation and the amounts, we can say that the limiting reactant would be cesium fluoride.  We calculate as follows:

11.0 mol CsF ( 1 mol </span>CsXeF7 / 1 mol CsF ) = 11.0 mol <span>CsXeF7</span>
6 0
3 years ago
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Serggg [28]

Answer:

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<em>Good luck, hope this helps :)</em>

5 0
2 years ago
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nadya68 [22]
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