All categories

3 years ago

What is the mass of a 200 kg object on Venus?

Physics

2 answers:

saw5 [17]3 years ago

8 0

A-200 kg
I hope this helped xx

GenaCL600 [577]3 years ago

3 0

<h2>Answer is 200 kg</h2>

First of all, divide the weight by the acceleration of the gravity, then multiply the result by acceleration of the gravity.

<h2>Weight = m × g</h2><h2 /><h2> 22.471910112359550 × 8.9 = 200 kg.</h2>

<h2>The answer still remains same. I hope you understood the concepts.</h2>

Bye

You might be interested in

Group 18 noble gases are inert because

hammer [34]

Answer:

Explanation:

have a full 8 electrons on the outermost ring

4 0

3 years ago

Opal adds 25 grams of salt to a one-liter glass beaker filled up to its volume mark with pure water. She stirs the water until t

Mars2501 [29]

By what i know i think that the answer would be A a homogeneous mixture.

5 0

3 years ago

Which of the following statements are true? Check all that apply. Check all that apply. The gravitational force between two obje

AveGali [126]

<em>The gravitational force between two objects is inversely proportional to the square of the distance between the two objects.</em>

The gravitational force between two objects is proportional to the product of the masses of the two objects.

The gravitational force between two objects is proportional to the square of the distance between the two objects. <em> no</em>

The gravitational force between two objects is inversely proportional to the distance between the two objects. <em> no</em>

The gravitational force between two objects is proportional to the distance between the two objects. <em> no</em>

The gravitational force between two objects is inversely proportional to the product of the masses of the two objects. <em> no</em>

3 0

3 years ago

Read 2 more answers

Beginning<br> lonic compounds are made up of a__<br> and a__

Romashka-Z-Leto [24]

Answer:

metal and non-metal

Explanation:

Ionic bonds are formed when a metal loses electrons and a non-metal gains said electrons.

3 0

3 years ago

Read 2 more answers

A spherical capacitor contains a charge of 3.00 nC when connected to a potential difference of 230 V. If its plates are separate

Assoli18 [71]

Answer:

Part(a): the capacitance is 0.013 nF.

Part(b): the radius of the inner sphere is 3.1 cm.

Part(c): the electric field just outside the surface of inner sphere is $\bf{2.81 \times 10^{4}~n~C^{-1}}$ .

Explanation:

We know that if 'a' and 'b' are the inner and outer radii of the shell respectively, 'Q' is the total charge contains by the capacitor subjected to a potential difference of 'V' and ' $\epsilon_{0}$ ' be the permittivity of free space, then the capacitance (C) of the spherical shell can be written as

$C = \dfrac{4 \pi \epsilon_{0}}{(\dfrac{1}{a} - \dfrac{1}{b})}~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)$

Part(a):

Given, charge contained by the capacitor Q = 3.00 nC and potential to which it is subjected to is V = 230V.

So the capacitance (C) of the shell is

$C &=& \dfrac{Q}{V} = \dfrac{3 \times 10^{-90}~C}{230~V} = 1.3 \times 10^{-11}~F = 0.013~nF$

Part(b):

Given the inner radius of the outer shell b = 4.3 cm = 0.043 m. Therefore, from equation (1), rearranging the terms,

$&& \dfrac{1}{a} = \dfrac{1}{b} + \dfrac{1}{C/4 \pi \epsilon_{0}} = \dfrac{1}{0.043} + \dfrac{1}{1.3 \times 10^{-11} \times 9 \times 10^{9}} = 31.79\\&or,& a = \dfrac{1}{31.79}~m = 0.031~m = 3.1~cm$

Part(c):

If we apply Gauss' law of electrostatics, then

$&& E~4 \pi a^{2} = \dfrac{Q}{\epsilon_{0}}\\&or,& E = \dfrac{Q}{4 \pi \epsilon_{0}a^{2}}\\&or,& E = \dfrac{3 \times 10^{-9} \times 9 \times 10^{9}}{0.031^{2}}~N~C^{-1}\\&or,& E = 2.81 \times 10^{4}~N~C^{-1}$

3 0

3 years ago