Answer:
Explanation:
By conservation of energy, speed of the ball going up = speed of ball coming down with the ball stops at the top.
Because the gravity acceleration is constant, by symmetry, half of total time, 6/2 = 3s, is for going up and the last 3s for coming down.
Consider the last 3s when the ball drops from top to bottom, the initial velocity = 0 and acceleration = 10m/s^2
distance traveled = initial velocity * time + 1/2 * acceleration * time^2
= 0*3 + 1/2*10*3^2
= 5*9
= 45m
So maximum height of the ball is 45m.
Answer:
a) 20 m/s
b) 37.5 m)s
Explanation:
Average speed = total distance ÷ total time
=> (a) average speed of a car that travels 400m in 20s
= 400/20 = 20 m/s
& (b) average speed of an athlete who runs 1500m in 4 minutes (or 4×60=240 seconds)
= 1500/240 = 37.5 m/s
The final velocity of the 14 kg object is 1.6 m/s in the same direction
Explanation:
We can solve this problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision. Therefore, we can write
where:
is the mass of the first object
is the initial velocity of the first object
is the final velocity of the first object
is the mass of the second object
is the initial velocity of the second object
is the final velocity of the second object
Re-arranging the equation and substituting the values, we find:
And the direction is the same as the initial direction, since it has the same sign.
Learn more about conservation of momentum:
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