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Genrish500 [490]
1 year ago
7

If a container of gas is at rest, the average velocity of molecules must be zero. yet theaverage speed is not zero. explain.

Physics
1 answer:
lakkis [162]1 year ago
5 0

To consider the molecule in gas at rest, suppose a container of gas at rest.

We know that velocity is a vector quantity and it includes direction but speed is a scalar quantity and it does not include a direction.  

Although the molecules are moving around a lot, they are only moving around within the fixed walls of the container. As the container isn't moving (given), the net velocity of the gas molecules is zero. Think about their random movements as vectors, then think about adding up all those vectors over time. They cancel each other out over time. So, the average velocity of a molecule in gas at rest is zero.  

But it's only the directions that cancel each other out, which is why the average speed (ignoring direction) is non-zero.

To learn more about average speed refer to the link:

brainly.com/question/12322912

#SPJ4

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3 years ago
Two charges +q and -q are situated at certain distance, at the point exactly midway betwee them what happens on electric field a
Luden [163]

Answer: Electric field is not zero but potential is zero

Explanation:

In science, charge, also recognized as electric charge, electrical charge, or electrostatic charge and expressed q, is a component of a unit of body that reveals the extent to which it has more or fewer electrons than protons.

Considering the direction of the electric field is of positive to negative charge. Therefore, it determination be toward due −q also due to both the charges.

But for potential, it is a scalar quantity, so the sum of potential due to all the charges will be zero.

Henceforth, the option (c) Electric field is not zero but potential is zero is the correct answer.

a incorect

From the above statements, we could conclude that option (c) Electric field is not zero, but potential is zero is the correct answer. So, the option (a) Electric field and potential both are zero is an incorrect solution.

b incorect

Among all the options, the option (c) Electric field is not zero but potential is zero is the correct answer.

Therefore, the option (b) Electric field is zero but potential is not zero is an incorrect solution

d) is incorrect

It has been explained that the option (c) Electric field is not zero but potential is zero is the correct answer.

Hence, the option (d) Electric field is not zero but potential is zero is an incorrect solution.

7 0
2 years ago
Which is another term for the free enterprise system
Naily [24]

Answer:

Another term for free enterprise system would be capitalism

6 0
3 years ago
Please help me this is important!
Mariulka [41]
145 Grams!
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4 0
3 years ago
Two asteroids identical to those above collide at right angles and stick together; i.e, their initial velocities were perpendicu
11111nata11111 [884]

Answer:

velocity = 62.89 m/s  in 58 degree measured from the x-axis

Explanation:

Relevant information:

Before the collision, asteroid A of mass 1,000 kg moved at 100 m/s, and asteroid B of mass 2,000 kg moved at 80 m/s.

Two asteroids moving with velocities collide at right angles and stick together. Asteroid A initially moving to right direction and asteroid B initially move in the upward direction.

Before collision Momentum of A = 1000 x 100 = $ 10^5$ kg - m/s in the right direction.

Before collision Momentum of B = 2000 x 80 = 1.6 x $ 10^5$  kg - m/s in upward direction.

Mass of System of after collision = 1000 + 2000 = 3000 kg

Now applying the Momentum Conservation, we get

Initial momentum in right direction = final momentum in right direction = $ 10^5$

And, Initial momentum in upward direction = Final momentum in upward direction = 1.6 x $ 10^5$

So, $ V_x = \frac{10^5}{3000} $  = $ \frac{100}{3} $  m/s

and $ V_y=\frac{160}{3}$  m/s

Therefore, velocity is = $ \sqrt{V_x^2 + V_y^2} $

                                   = $ \sqrt{(\frac{100}{3})^2 + (\frac{160}{3})^2} $

                                   = 62.89 m/s

And direction is

tan θ = $ \frac{V_y}{V_x}$     = 1.6

therefore, $ \theta = \tan^{-1}1.6 $

                   = $ 58 ^{\circ}$  from x-axis

4 0
3 years ago
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