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3 years ago

12

roy gets 10% extra time in school exams. If Roy gets 1 hour 33 minutes and 30 seconds to complete his maths exam, how long do mo

st students get.

1 answer:

Yuliya22 [10]3 years ago

6 0

Answer:

1 Hour 25 Minutes

You might be interested in

Hector invests $20,000 at age 21. He hopes the investment will be worth $200,000 when he turns 40. If the interest compounds con

KiRa [710]

Answer:

12.12%

Step-by-step explanation:

We have that the formula is given by:

A = p * e ^ (r * t)

From here, we know that A = 200000; p = 20000 and the time we can calculate 40 - 21 = 19

if we replace we have:

200000 = 20000 * e ^ (19 * r)

we must calculate r:

e ^ (19 * r) = 200000/20000

e ^ (19 * r) = 10

19 * r = ln 10

r = ln 10/19

r = 0.1212

In other words, the rate of growth is 12.12%

8 0

3 years ago

Read 2 more answers

Is 2x+4+3(2x-1) equivalent to 8x-2

almond37 [142]

Answer: 2x+4+3(2x-1) is not equivalent to 8x-2. it is equivalent to 8x+1

Step by step solution:

Step 1 :

Equation at the end of step 1 :

(2x + 4) + 3 • (2x - 1)

Step 2 :

Final result :

8x + 1

3 0

3 years ago

What is the simplified answer to this? thank you :)<br><br><img src="https://tex.z-dn.net/?f=9%20%5Csqrt%7B245%7D%20" id="TexFor

Svetradugi [14.3K]

Answer:

$63 \sqrt[ \: ]{5}$

Step-by-step explanation:

$9 \sqrt{245}$

$9 \sqrt{ {7}^{2} \times 5 }$

$9 \times 7 \sqrt{5}$

$63 \sqrt{5}$

6 0

3 years ago

What is the solution set for 2x+5y>-1 and 4x-3<-3?

bekas [8.4K]

PROBLEM ONE

•

Solving for x in 2x + 5y > -1.

•

Step 1 ) Subtract 5y from both sides.

2x + 5y > -1

2x + 5y - 5y > -1 - 5y

2x > -1 - 5y

Step 2 ) Divide both sides by 2.

2x > -1 - 5y

$\displaystyle\frac{2x}{2} > \displaystyle\frac{-1 - 5y}{2}$

$\displaystyle\ x > \frac{-1 - 5y}{2}$

So, the solution for x in 2x + 5y > -1 is...

$\displaystyle\ x > \frac{-1 - 5y}{2}$

•

Solving for y in 2x + 5y > -1.

•

Step 1 ) Subtract 2x from both sides.

2x + 5y > -1

2x - 2x + 5y > -1 - 2x

5y > -1 - 1x

Step 2 ) Divide both sides by 5.

5y > -1 - 1x

$\displaystyle\frac{5x}{5} > \frac{-1 -1x}{5}$

$\displaystyle\ x > \frac{-1 -1x}{5}$

So, the solution for y in 2x + 5y > -1 is...

$\displaystyle\ x > \frac{-1 -1x}{5}$

•

PROBLEM TWO

•

Solving for x in 4x - 3 < -3.

•

Step 1 ) Subtract 3 from both sides.

4x - 3 < -3

4x -3 - 3 < -3 - 3

4x < 0

Step 2 ) Divide both sides by x.

4x < 0

$\displaystyle\frac{4x}{4}$

x < 0

So, the solution for x in 4x - 3 < -3 is...

x < 0

•

•

- <em>Marlon Nunez</em>

7 0

3 years ago

Solve for x. X+5/2=b<br> Please help!!

melomori [17]

<span> X+5/2=b
Subtract 5/2 from both sides
Final Answer: x= b-5/2</span>

4 0

4 years ago