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3 years ago

7

Simplify the expression

1 answer:

uysha [10]3 years ago

8 0

In extract form 23/20 with mixed numbers -1 3/20

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640, 160, 40, 10, ...

WARRIOR [948]

Answer:

Option 3 and 5 are correct

Step-by-step explanation:

We have given a geometric series 640,160,40,10....

Common ratio of geometric series is $r=\frac{a_2}{a_1}$

$r=\frac{160}{640}=\frac{1}{4}$

Here our common ratio is less than zero

It will show the graph of exponential decay

Hence, option 5 is correct.

The general term of geometric series is $a_n=a\cdotr^(n-1)$

Domain will be all natural numbers since, geometric series take only natural numbers.

Here, values of "n" is domain

Hence, option 3 is correct.

Range can be any positive real numbers not only natural number

Range is the value of $a_n$

Hence, option 4 is discarded.

Graph can not be linear of a geometric series being exponential

Hence, option 2 is discarded.

Option 1 is discarded because it is exponential decay function so it can not be exponential growth.

Therefore, Option 3 and 5 are correct.

4 0

3 years ago

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Least fraction from least to greatest 8/9, 17/29,14/29,9/29

aniked [119]

17/29, 14/29, 9/29, 8/9 Hope this helps

7 0

4 years ago

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Anybody can guess these three question gets a last laugh bundle code

Nady [450]

3/4 is the answer I think maybe

8 0

3 years ago

2x-5y=9<br> 3x+4y=2<br> solve the simultaneous equations

wariber [46]

$\huge\boxed{x=2;\ y=-1}$

$\left\{{{2x-5y=9}\atop{3x+4y=2}}\right$

First, we will solve the second equation for $x$ . Subtract $4y$ from both sides of the second equation.

$3x=2-4y$

Divide both sides of the second equation by $3$ .

$x=\frac{2}{3}-\frac{4}{3}y$

$\left\{{{2x-5y=9}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right$

Substitute the value of $x$ from the second equation into the first.

$\left\{{{2(\frac{2}{3}-\frac{4}{3}y)-5y=9}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right$

$2(\frac{2}{3}-\frac{4}{3}y)-5y=9$

We will solve the first equation for $y$ .

Distribute the $2$ to the $(\frac{2}{3}-\frac{4}{3}y)$ .

$\frac{4}{3}-\frac{8}{3}y-5y=9$

Combine the like terms.

$\frac{4}{3}-\frac{23}{3}y=9$

Add $\frac{4}{3}$ on both sides.

$-\frac{23}{3}y=9-\frac{4}{3}$

$-\frac{23}{3}y=\frac{23}{3}$

Divide both sides by $\frac{23}{3}$ .

$-y=1$

Multiply both sides by $-1$ .

$y=\boxed{-1}$

Substitute the value of $y$ into the second equation.

$\left\{{{y=-1}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right$

$x=\frac{2}{3}-\frac{4}{3}*-1$

Multiply.

$x=\frac{2}{3}+\frac{4}{3}$

Add.

$x=\frac{6}{3}$

$x=\boxed{2}$

5 0

3 years ago

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What is 5/8 + 3/4 because I am doing fractions right know

pantera1 [17]

$\frac{5}{8} + \frac{3}{4} =$

So, $\frac{5}{8} + \frac{3}{4} * \frac{2}{2} = \frac{5}{8} + \frac{6}{8} = \frac{11}{8}$

Simplified as mixed number equals to $1 \frac{3}{8}$

(Keep in mind that the LCM was 8.)

4 0

4 years ago

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