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nikitadnepr [17]
3 years ago
15

Suppose you combine two substances but no chemical reaction occurs. Which of the following best describes the result?

Chemistry
1 answer:
FromTheMoon [43]3 years ago
7 0
What best describes the result is a mixture
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Which answer provides the correct name for name the following hydrocarbon?
natulia [17]
I think the correct answer would be the third option. The correct name for the hydrocarbon described above would be 2-heptyne. It has a chemical formula written as CH3 - CH2 - CH2 - CH2 - C ≡ C - CH3. Counting the number of carbons, we have 7 carbon atoms so we use the prefix hepta-. Since it has a triple bond then it is an alkyne. So, it would be named as heptyne. The triple bond is located on the second carbon atom so we write 2 before the name to indicate the location of the triple bond. The name of the compound would be 2-heptyne.
4 0
3 years ago
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Science.... <br> homework!
Leokris [45]
The answer to this question is 2 and 3
5 0
3 years ago
2Al + 6HCl → 2AlCl3 + 3H2<br> If 85.0 grams of HCl react, how many moles of H2 are produced?
Murrr4er [49]

Answer:

1.17 mol

Explanation:

Step 1: Write the balanced equation

2 Al + 6 HCl → 2 AlCl₃ + 3 H₂

Step 2: Calculate the moles corresponding to 85.0 g of HCl

The molar mass of HCl is 36.46 g/mol.

85.0 g × 1 mol/36.46 g = 2.33 mol

Step 3: Calculate the number of moles of H₂ produced from 2.33 moles of HCl

The molar ratio of HCl to H₂ is 6:3.

2.33 mol HCl × 3 mol H₂/6 mol H₂ = 1.17 mol H₂

8 0
2 years ago
When the cell splits, they have a nucleus with complete genetic material for the new daughter cells. What is this genetic materi
nika2105 [10]

Answer:

chromosomes

Explanation:

;)...................

3 0
2 years ago
A 20.0g sample of metal with a specific heat of 5 J/(g°C) raised it's initial temperature to 40.0 when 500J heat was added. What
slavikrds [6]

The initial temperature of the metal = 35 °C

<h3>Further explanation</h3>

Heat can be formulated :

Q = m . c . ΔT

Q = heat, J

c = specific heat, J/g C

ΔT = temperature, °C

m = 20 g

c = 5 J/(g°C)

Q = 500 J

T₁ = 40 C

the initial temperature :

\tt \Delta t(T_2-T_1)=\dfrac{Q}{m.c}\\\\40-T_1=\dfrac{500}{20.5}\\\\40-T_1=5\\\\T_1=35^oC

3 0
2 years ago
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