1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Masteriza [31]
3 years ago
15

IM ON A TIMER! What are the main types of star clusters? Check all that apply.

Chemistry
2 answers:
jekas [21]3 years ago
8 0

There are globular and open star clusters, but there are no binary, eclipsing, or wobbling ones.


mojhsa [17]3 years ago
8 0

Answer:  

globular

open

Explanation:

A star cluster is a small group of stars found in galaxy. There are two types of star clusters:

Open and globular.

An open cluster contains about 100 stars. These are found in disk of galaxy. These are less dense group of stars containing  young one.

A globular cluster is has thousands of stars tightly packed together. These are found in halo of galaxy and contain relatively old stars.

You might be interested in
Given substances f2, kr, cl2 and hbr rank them with respect to the highest boiling point?
Inessa05 [86]

The Hbr has highest boiling point followed by Kr , Cl_{2} and F_{2} .

The Hbr has  highest boiling point due to presence of intermolecular H-bonding that is hydrogen bonding.

The electronegativity of bromine is greater than hydrogen atom. The electronegativity difference hydrogen atom and bromine atom is high. So, due to this a positive dipole is generated at hydrogen atom and partial negative charge, these partial charge is called dipole. In a HBr molecule one H-atom attracted by Br-atom of another atom by force of attraction and this partial force of attraction is called H-bonding.

Other all given molecules are arrange according to its molecular mass because boiling points is directly proportional to the molecular mass of molecule.

learn more about boiling point

brainly.com/question/2153588

#SPJ4

3 0
1 year ago
Not easily changed
Advocard [28]
I would say when an atom has its valence electron shell filled like a noble gas has, it is not easily changed.

I’m not entirely sure of what you’re asking, but if you’re talking about bonding then it would be an ionic bond that is not easily changed.
6 0
3 years ago
Suppose the mole number of Ca2+ ions in a 50 mL water sample is quantified as 1.5 × 10−5 mol. What is the concentration of Ca2+
Anna11 [10]
\frac{1.5x 10^{-5} mol  Ca^{2+}}{50ml}  ( \frac{1 mol CaC O_{3} }{1 mol  Ca^{2+} } )( \frac{100,000 ppm}{1 molCaC O_{3}/L } ) \\ =0.0300234
5 0
3 years ago
Read 2 more answers
Why are gamma rays not affected by a magnet as they Passover it
avanturin [10]
Gamma rays are not magnetic
7 0
4 years ago
Read 2 more answers
To decrease the rate of reaction you would ... *
STALIN [3.7K]
Answer: it’s number 2 add a catalyst

Hopefully this helped :)
4 0
3 years ago
Read 2 more answers
Other questions:
  • Filtration can be used to separate mixtures based on
    14·2 answers
  • What is the #1 or main component of the earths ancient atmosphere?
    15·1 answer
  • How many grams of sugar must be dissolved in 150 mL of water to make a solution with a concentration of 0.6 g/mL?
    12·1 answer
  • If I have a 32 fl oz os a solution that has 62% alcohol, how much of a solution of 91% alcohol do I need to add to get a final s
    7·1 answer
  • Please Help Me! Question is on link down below!
    7·1 answer
  • A 19.45 gram sample of copper is heated in the presence of excess iodine. A metal iodide is formed with a mass of 58.30 g. Deter
    10·1 answer
  • What forces typically hold ionic solids together?
    5·1 answer
  • Balance the equations for the formation of cations from neutral atoms
    7·1 answer
  • An example of polytamic anoin would be a. Ca+2 b. NH4+ c. F d. PO4-3
    8·1 answer
  • 50 trillion (5.00 x 1013) Angstrom is equivalent to 10900 cubit. If 108 Angstrom = 1 cm (exactly), how many m are there in 1.00
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!