All categories

2 years ago

The weight of an object never changes. A. True B. False

Chemistry

2 answers:

Shalnov [3]2 years ago

6 0

Answer: false .

Explanation: Weight is the measure of the force of gravity on an object. The mass of an object will never change, but the weight of an item can change based on its location.

For example, you may weigh 100 pounds on Earth, but in outer space you would be weightless.Mass never changes. Weight, which is a product of mass times gravity, may change due to a difference in gravity

HOPE IT HELPS FRIEND!

Alla [95]2 years ago

3 0

Answer:

$\huge\boxed{\textbf{False}}$

Explanation:

Definition of weight:

The gravitational force acting on a body is called weight.

Explanation:

The weight of the body changes with different factors concerned e.g. height h, acceleration due to gravity g etc.

We know that,

W = mg

Mass is a constant quantity, however g changes with the altitude or place. Consequently, weight also does not remain constant.

Example:

An object having mass 1 kg will have a weight of 9.8 N on Earth while its weight on moon will be 1.6 N due to the difference in the values of g.

$\rule[225]{225}{2}$

You might be interested in

The________ cation will precipitate after the_________ step. Then the _________cation will precipitate after the________ step.

Novay_Z [31]

Answer:

f. Sn^4+

c. second

e. Al^3+

d. third

Explanation:

This question comes from a quantitative analysis showing the flowchart of a common scheme for identifying cations.

Now, from the separation scheme, Let's assume that Sn⁴⁺ & Al³⁺ were given; Then, Yes, the separation will work.

However, there will be occurrence of precipitation after the 1st step1.

So, the Sn⁴⁺ cation will precipitate after the second step. Then the Al³⁺ cation will precipitate after the third step.

8 0

2 years ago

A 25.0 g sample of an alloy was heated to 100.0 oC and dropped into a beaker containing 90 grams of water at 25.32 oC. The tempe

elena55 [62]

Answer:

The specific heat of the alloy $C_{a} = 0.37 \frac{KJ}{Kg K}$

Explanation:

Mass of an alloy $m_{a}$ = 25 gm

Initial temperature $T_{a}$ = 100°c = 373 K

Mass of water $m_{w}$ = 90 gm

Initial temperature of water $T_{w}$ = 25.32 °c = 298.32 K

Final temperature $T_{f}$ = 27.18 °c = 300.18 K

From energy balance equation

Heat lost by alloy = Heat gain by water

$m_{a}$ $C_{a}$ [ $T_{a}$ - $T_{f}$ ] = $m_{w}$ $C_w$ ( $T_{f}$ - $T_{w}$ )

25 × $C_{a}$ × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)

$C_{a} = 0.37 \frac{KJ}{Kg K}$

This is the specific heat of the alloy.

4 0

3 years ago

Be sure to answer all parts.The equilibrium constant, Kc, for the formation of nitrosyl chloride from nitric oxide and chlorine,

djverab [1.8K]

Answer: The reaction proceeds in the forward direction

Explanation:

For the given chemical equation:

$2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)$

Relation of $K_p\text{ with }K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta n_g}$

where,

$K_p$ = equilibrium constant in terms of partial pressure = ?

$K_c$ = equilibrium constant in terms of concentration = $6.5\times 10^4$

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = $35^oC=[35+273]K=308K$

$\Delta n_g$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-3=-1$

Putting values in above equation, we get:

$K_p=6.5\times 10^4\times (0.0821\times 500)^{-1}\\\\K_p=1583.43$

$K_p$ is the constant of a certain reaction at equilibrium while $Q_p$ is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.