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kupik [55]
2 years ago
5

The weight of an object never changes. A. True B. False

Chemistry
2 answers:
Shalnov [3]2 years ago
6 0

Answer: false .

Explanation: Weight is the measure of the force of gravity on an object. The mass of an object will never change, but the weight of an item can change based on its location.

For example, you may weigh 100 pounds on Earth, but in outer space you would be weightless.Mass never changes. Weight, which is a product of mass times gravity, may change due to a difference in gravity

HOPE IT HELPS FRIEND!

Alla [95]2 years ago
3 0

Answer:

\huge\boxed{\textbf{False}}

Explanation:

<u>Definition of weight:</u>

  • The gravitational force acting on a body is called weight.

<u>Explanation:</u>

The weight of the body changes with different factors concerned e.g. height h, acceleration due to gravity g etc.

We know that,

W = mg

Mass is a constant quantity, however g changes with the altitude or place. Consequently, weight also does not remain constant.

<u>Example:</u>

An object having mass 1 kg will have a weight of 9.8 N on Earth while its weight on moon will be 1.6 N due to the difference in the values of g.

\rule[225]{225}{2}

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Find the number of CoCl2 units present in a 0.78 mol sample.
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\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

1 mole of \sf{ COCl_2} has 6.022 × 10²³ molecules of the given compound.

So, 0.78 mole of \sf{COCl_2} will have ~

\qquad \sf  \dashrightarrow \: 0.78 \times 6.022 \times 10 {}^{23}

\qquad \sf  \dashrightarrow \:  \approx4.7 \times 10 {}^{23}  \:  \:  \: molecules

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2 years ago
Is the gravity a black hole strong enough to keep light from escaping True or False
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Answer:

The gravitational pull of a black hole is so strong that nothing, not even light, can escape once it gets too close. ... Moving at close to the speed of light, these particles ricochet off the event horizon and get hurled outward along the black hole's axis of rotation

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2 years ago
Elements in the 2nd family/group gain or lose electrons? *
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2 years ago
A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the
Vlad1618 [11]

A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

<h3>What is Combined Gas Law ?</h3>

This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.

It is expressed as

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where,

P₁ = first pressure

P₂ = second pressure

V₁ = first volume

V₂ = second volume

T₁ = first temperature

T₂ = second temperature

Now put the values in above expression we get

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}

P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}

P₂ = 1.76 atm

Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

Learn more about the Combined gas Law here: brainly.com/question/13538773

#SPJ4

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2 years ago
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Its a form of anaesthesia used by dentists 

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