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bezimeni [28]
3 years ago
7

Calculate the enthalpy change when 4.00 mol Cl2O7 is produced according to the following balanced equation:

Chemistry
1 answer:
marissa [1.9K]3 years ago
8 0

So the equation is,

2Cl2(g) + 7O2(g) + 130kcal -> 2Cl2O7(g)

from this , ΔH°rxn=130kcal.mol^{-1}

mol^{-1} is mentioned because it is for per mole of reaction. So for 4. moles of the product 2Cl_{2} O_{7} we need 4/2 moles of reaction to be used to calculate associated enthalphy change for the reaction.

Therefore4/2*130=260 kcal


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34g aluminum are combined with 39g chlorine gas which is the limiting reactant
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The limiting reactant is chlorine (Cl2).

<u>Explanation</u>:

Limiting reactant is the amount of product formed which gets limited by the reagent without continuing it.

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Number of moles Al present = 34 g Al x 1 mole Al / 26.98 g

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Dividing each reactant by it's coefficient in the balanced equation obtains:

1.260 moles Al / 2 = 0.63 g moles of Al

1.11 moles Cl2 / 3 = 0.36 g moles of Cl2

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Here the Limiting reactant is Cl2.

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<em />

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