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Nimfa-mama [501]
2 years ago
9

You want to get a pizza the pizza is 14.00 but 50% off. How much will the pizza cost with 8% delivery tax Fees included?

Mathematics
1 answer:
nignag [31]2 years ago
4 0

Answer:

7.56

Step-by-step explanation:

14x.50(the remainder after you subtract the percent from 100) = 7

8% of 7 is 0.56

7+0.56=7.56

You might be interested in
If one endpoint of a line segment is (2, 8) and the midpoint is (-4, 7), what is the other endpoint? (8, -5)
Pepsi [2]

( - 10, - 22 )

using the midpoint formula,

let the other endpoint have coordinates (x, y) then

\frac{1}{2} (2 + x ) = - 4 ( multiply through by 2 )

2 + x = - 8 ( subtract 2 from both sides ) then

x = -8 - 2 = - 10 ← value of x-coordinate

Similarly for y-coordinate

\frac{1}{2} (8 + y ) = - 7 ( multiply through by 2 )

8 + y = - 14 ( subtract 8 from both sides )

y = - 14 - 8 = - 22 ← y -coordinate

the other endpoint is ( - 10, - 22 )




7 0
3 years ago
The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it
brilliants [131]

Answer:

(a) 11.25 and 1.68  

(b) 0.1651

(c) 0.3903

(d) 0.6865

Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 15

             r = number of success

             p = probability of success which in our question is % of cases in

                  which customer problems are resolved on the same day, i.e.;75%

So, here X ~ Binom(n=15,p=0.75)

(a) Expected number of problems to be resolved today = E(X)

            E(X) = \mu = n * p = 15 * 0.75 = 11.25

    Standard deviation = \sigma = \sqrt{n*p*(1-p)} = \sqrt{15*0.75*(1-0.75)} = 1.68

(b) Probability that 10 of the problems can be resolved today = P(X = 10)

     P(X = 10) = \binom{15}{10}0.75^{10}(1-0.75)^{15-10}

                    = 3003*0.75^{10} *0.25^{5} = 0.1651

(c) Probability that 10 or 11 of the problems can be resolved today is given by = P(X = 10) + P(X = 11)

    = \binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}

    = 3003*0.75^{10} *0.25^{5} + 1365*0.75^{11} *0.25^{4} = 0.3903

(d) Probability that more than 10 of the problems can be resolved today is

    given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)  

= \binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}

= 1365*0.75^{11} *0.25^{4} + 455*0.75^{12} *0.25^{3}+105*0.75^{13} *0.25^{2} + 15*0.75^{14} *0.25^{1}+1*0.75^{15} *0.25^{0}

= 0.6865

3 0
3 years ago
A hiker carried 1 gallon of water on a hike. She drank 1/2 of the water when she stopped to rest and gave an equal amount of the
m_a_m_a [10]

Answer:

The answer to your question is 1/8

Step-by-step explanation:

Data

Total volume = 1 gallon

Water drank by the hiker = 1/2

Water drank by each of his friends = ?

Process

1.- Calculate the water that he gave to his friends

Water gave to his friends = 1 - 1/2

                                          = 1/2

2.- Calculate the amount of water each friend received.

            1/2 ÷ 4 = 1/8

3.- Conclusion

Each of the friends received 1/8 of the gallon.              

6 0
3 years ago
According to government data, 20% of employed women have never been married. If 10 employed women are selected at random, what i
Ierofanga [76]

Answer:

a) P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302

b) P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)

P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107

P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268

P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302

And replacing we got:

P(X\leq 2) = 0.107+0.268+0.302=0.678

c) For this case we want this probability:

P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302

P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268

P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107

And replacing we got:

P(X \geq 8) = 0.677

And replacing we got:

P(X\geq 8)=0.0000779

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Let X the random variable of interest, on this case we now that:  

X \sim Bin (n=10 ,p=0.2)

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Let X the random variable "number of women that have never been married" , on this case we now that the distribution of the random variable is:  

X \sim Binom(n=10, p=0.2)  

Part a

We want to find this probability:

P(X=2)

And using the probability mass function we got:

P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302

Part b

For this case we want this probability:

P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)

We can find the individual probabilities and we got:

P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107

P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268

P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302

And replacing we got:

P(X\leq 2) = 0.107+0.268+0.302=0.678

Part c

For this case we want this probability:

P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302

P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268

P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107

And replacing we got:

P(X \geq 8) = 0.677

3 0
3 years ago
If 2/3 of amount x is 60, then what is 4/5 of x
frozen [14]
I think it's 72 then?
8 0
3 years ago
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