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Zielflug [23.3K]
3 years ago
11

Can someone answer 6x=-7?

Mathematics
2 answers:
OLga [1]3 years ago
6 0

Answer:

x = - 7/6

Step-by-step explanation:

First, divide both sides of the equation by the same term:

6x = - 7

6x/6 = -7/6

Then simplifly and you'll get your answer! ( I won't show how to simplify but if you want to know tell me!)

x = - 7/6

Maurinko [17]3 years ago
4 0

Answer:

Divide each term in 6x=−7 by 6 and simplify.

Step-by-step explanation:

Exact Form:

x=−7/6

Decimal Form:

x=−1.1¯6

Mixed Number Form:

x=−1 1/6

You might be interested in
Alex, Ian, and Ric together sold 48 tickets for the school fund-raiser. Alex sold 11 tickets and Ian sold 18 tickets. How many t
eimsori [14]
To determine the number of tickets that Ric sold, subtract from the total tickets sold the sum of the number of tickets sold by Alex and Ian. This is mathematically shown as, 

                        tickets (Ric) = tickets (total) - (tickets (Alex) + tickets (Ian))

                                  tickets (Ric) = 48 - (11 + 18) = 19

Hence, Ric sold 19 tickets for the fundraising. 
8 0
3 years ago
Read 2 more answers
some numbers added to -11 is 37.divide this number by -12.then multiply by -8.what is the final number?
LUCKY_DIMON [66]
Since some number added to -11 is 37, we must do 37- (-11),  which is 48. Then we check our work and find that 48+-11 is indeed 37. Now we divide 48 by -12, which is -4, multiply by -8 and get a final answer of 32.
6 0
3 years ago
Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

The integral itself can be evaluated by writing the root and exponent of the variable u as:   \sqrt[8]{u^3} =u^{\frac{3}{8}

Then, an antiderivative of this is: \frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}

which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

Since this this function u^{\frac{3}{8} is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}

5 0
3 years ago
Help me on this please
kolbaska11 [484]
The answer : C
Yea its C
5 0
2 years ago
Please help asap! Correct answers only!
ozzi

Answer:

$98100

Step-by-step explanation:

Using the given formula :

I = P × R × T

I = 90000 × 3/100 × 3

I = $8100

He saves = 8100 + 90000 = $98100

6 0
3 years ago
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