A reaction that produces 14.2 grams of a product and the theoretical yield of that product is 17.1 grams is true for the following statements :
The percent yield of the product is 83.0%
The actual yield of the product is 14.2 grams.
<h3>Percentage Yield:</h3>
Percent yield is the percent ratio of actual yield to the theoretical yield.
Mathematically,
percent yield = actual yield / theoretical yield x 100%
actual yield = 14.2 grams
theoretical yield = 17.1 grams
percentage yield = 14.2 / 17.1 × 100%
percentage yield = 83.0409356725 %
percentage yield = 83.0 %
Therefore,
The percent yield of the product is 83.0%
The actual yield of the product is 14.2 grams.
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Answer:
The answer to your question is: KNO₃
Explanation:
AgNO3 + KCl → AgCl + −−−−
A. KNO3 this option is correct because it is a double replacement reaction then potassium must attached to NO₃.
B. KOH this product is not possible because there is no water to form OH⁻ ions.
C. Ag2K this product is not possible because both Ag and K are metals, then it is difficult that they attach.
D. KN2O This product is imposible to form, this option is wrong.
Answer : The partial pressure of
and
is, 216.5 mmHg and 649.5 mmHg
Explanation :
According to the Dalton's Law, the partial pressure exerted by component 'i' in a gas mixture is equal to the product of the mole fraction of the component and the total pressure.
Formula used :


So,

where,
= partial pressure of gas
= mole fraction of gas
= total pressure of gas
= moles of gas
= total moles of gas
The balanced decomposition of ammonia reaction will be:

Now we have to determine the partial pressure of
and 

Given:


and,

Given:


Thus, the partial pressure of
and
is, 216.5 mmHg and 649.5 mmHg