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mezya [45]
3 years ago
14

List the sequence of events that occurred in the area represented by the profile above.

Chemistry
1 answer:
Fittoniya [83]3 years ago
7 0

1. Igneous intrusion Y formed.

2. The shale layer was deposited.

3. Igneous intrusion X formed.

4. The limestone layer was deposited.

5. The mudstone layer was deposited.

B 1. The mudstone layer was deposited.

2. The limestone layer was deposited.

3. The shale layer was deposited.

4. Igneous intrusion Y was forced onto the mudstone, limestone, and shale.

5. Igneous intrusion X was forced onto the mudstone, limestone, and shale.

C 1. Igneous intrusion X formed.

2. Igneous intrusion Y formed.

3. The shale layer was deposited.  

4. The limestone layer was deposited.

5. The mudstone layer was deposited.

D 1. The layer of mudstone was deposited.

2. The layer of limestone was deposited.

3. Igneous intrusion Y was forced onto the mudstone and limestone.

4. The shale layer was deposited.

5. Igneous intrusion X was forced over the mudstone, limestone, and shale

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Which of these statement(s) is/are true about a balloon filled with 1.00 mol N2 (g) at STP?
lara [203]

Answer:

I. The balloon has a volume of 22.4L

III. The balloon contains 6.022x10^23 molecules.

Explanation:

At stp, it has been proven that 1mole of a gas occupy 22.4L.

Therefore, option (i) is correct.

The molar mass N2 = 14.01 x 2 = 28.02g/mol

Number of mole of N2 = 1 mole

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Mass of N2 = 1 x 28.02 = 28.02g.

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From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This implies that 1 mole of N2 also contains 6.02x10^23 molecules

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The correct options to the question are:

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7 0
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Read 2 more answers
At constant pressure, which of these systems do work on the surroundings? A ( s ) + B ( s ) ⟶ C ( g ) A(s)+B(s)⟶C(g) 2 A ( g ) +
Tju [1.3M]

Correct question:

At constant pressure, which of these systems do work on the surroundings?

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

(c) A ( g ) + B ( g ) ⟶ C ( g )

(d) 2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

Answer:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

Explanation:

Work done by a system on the surroundings at a constant pressure is given as;

W = -PΔV

Where;

ΔV is gas expansion, that is final volume of the gas minus initial volume of the gas must be greater than zero.

Part (a)

A ( s ) + B ( s ) ⟶ C ( g )

ΔV = 1 - (0) = 1 (expansion)

Part (b)

2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

ΔV = 5 - ( 2+ 2) = 1 (expansion)

Part (c)

A ( g ) + B ( g ) ⟶ C ( g )

ΔV = 1 - ( 1 + 1) = -1 (compression)

Part (d)

2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

ΔV = 3 - ( 4) = -1 (compression)

Thus, systems where there is gas expansion are in part (a) and part (b). The correct answers are:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

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