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3 years ago

14

Deciding that she was thirsty, Ms. Smith decided to mix up some lemonade using 2 tablespoons of lemonade, and 2 cups of water. W

hat is the solute and solvent?

1 answer:

balandron [24]3 years ago

8 0

Explanation:

solute is the substance being dissolved so that is the 2 tablespoons of lemonade and the 2 cups of water is the solvent.

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Which of the following is a type of kinetic energy.

dexar [7]

Kinetic energy is energy in motion. B, a rolling ball would be your answer because a rolling ball is energy that is moving. The rest of the answers are wrong because the actions do not use kinetic energy.

6 0

3 years ago

The breaking buffer that we use this week contains 10mM Tris, pH 8.0, 150mM NaCl. The elution buffer is breaking buffer that als

olasank [31]

Answer:

A breakdown of the breaking buffer was first listed with its respective component and their corresponding value; then a table was made for the stock concentrations in which the volume that is being added was determined by using the formula $M_1*V_1 = M_2*V_2$ . It was the addition of these volumes altogether that make up the 0.25 L (i.e 250 mL) with water

Explanation:

Given data includes:

Tris= 10mM

pH = 8.0

NaCl = 150 mM

Imidazole = 300 mM

In order to make 0.25 L solution buffer ; i.e (250 mL); we have the following component.

Stock Concentration Volume to be Final Concentration

added

1 M Tris 2.5 mL 10 mM

5 M NaCl 7.5 mL 150 mM

1 M Imidazole 75 mL 300 mM

$M_1*V_1 = M_2*V_2$ . is the formula that is used to determine the corresponding volume that is added for each stock concentration

The stock concentration of Tris ( 1 M ) is as follows:

$M_1*V_1 = M_2*V_2$ .

$1*V_1= 0.01 M *250mL\\V_1 = 2.5mL$

The stock concentration of NaCl (5 M ) is as follows:

$M_1*V_1 = M_2*V_2$ .

$1*V_1= 0.15 M *250mL\\V_1 = 7.5mL$

The stock concentration of Imidazole (1 M ) is as follows:

$M_1*V_1 = M_2*V_2$ .

$1*V_1= 0.03 M *250mL\\V_1 = 75mL$

Hence, it is the addition of all the volumes altogether that make up 0.25L (i.e 250 mL) with water.

5 0

3 years ago

Please help this is due tonight

Elenna [48]

4. the nervous system uses electrical impulses to send messages through neurons while endocrine glands use hormones to send messages

5. Hormones are released from the endocrine glands

6. a. neck
b. Chest

7. help regulate important functions, such as growth, blood pressure and reproduction; it is small and small and bean shaped.

8. produces hormones that regulate the body's metabolic rate controlling heart, muscle and digestive function, brain development.

9. regulate your metabolism, immune system, blood pressure, respond to stress etc.

10. “enzymes” - break down sugars, fats, and starches

11. cells are unable to use glucose (can’t break down sugar to use as energy)

5 0

3 years ago

1. Each substance written to the right of the arrow in a chemical equation is a

Scorpion4ik [409]

Answer: product

Explanation:

Each substance written to the right of the arrow in a chemical equation is referred to as a product.

When writing a chemical equation, the substance that's written to the left of arrow in the equation is the reactants.

On the other hand which is the right side is the product.

5 0

2 years ago

Extend your thinking: The slow decay of radioactive materials can be used to find the age of rocks, fossils, and archaeological

lisov135 [29]

The age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.

<h3>What is the half-life of a radioactive material?</h3>

The half-life of a radioactive material is the time taken for half the atoms present in the material to decay or disintegrate.

The half-life, $t_\frac{1}{2}$ , the age, t, and amount remaining, $A_{r}$ , of a radioactive material are related by the formula below:

$t = \frac{t_\frac{1}{2}*A_{r}}{-ln2}$

Half-life of carbon-14 = 6000 years

For the Egyptian papyrus with 63% of its original carbon-14 atoms: $t = \frac{6000*0.63}{-0.63} = 4000\:years$

For the Aboriginal charcoal with 22% of its original carbon-14 atoms:

$t = \frac{6000*0.22}{-0.63} = 13106.5\:years$

For the Mayan headdress with 79% of its original carbon-14 atoms:

$t = \frac{6000*0.79}{-0.63} = 2040\:years$

Neanderthal skull with 3% of its original carbon-14 atoms:

$t = \frac{6000*0.03}{-0.63} = 30353\:years$

Therefore, the age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.

Learn more about half-life at: brainly.com/question/26689704

#SPJ1

6 0

2 years ago