If you have at least as many equations as your have unknown variables, the 'system' is solvable (unless the equations are copies of eachother).

In this case, isolate one letter and plug it in the other. I'm going for the 2a in the bottom one (it doesn't matter)

2a - 4b = 12 => (divide by two and move the b's to the other side)

a = 6 + 2b. (plug this one into the top equation)

4(6+2b) + 6b = 10 => 24+8b+6b = 10 => 24 + 14b = 10 => 14b = -14 => b=-1

a = 6 + -2 = 4.

So a=4 and b=-1.

4 0

3 years ago

Find sec A and cot B exactly if a = 8 and b = 7.

Shtirlitz [24]

Answer:

sec A= 1.01 and cot B =8.25

Step-by-step explanation:

Given :

sec A and cotB if a =8 and b=7

Now,

= $sec A=\frac{1}{cos A} \\\\\frac{1}{cos 8} \\\\\frac{1}{0.99} \\1.01$

and

$cot B=\frac{cosB}{sin B} \\cotB=\frac{cos 7}{sin7} \\cot B =\frac{0.99}{0.12} \\cot B =8.25$

Therefore, answer will be sec A= 1.01 and cot B =8.25

8 0

2 years ago

Will bought 3 college textbooks. One cost $32, one cost $45, and one cost $39. What is the average price of his books? Choose th

ch4aika [34]

I think the correct answer among the choices presented above is option B. Average is the sum of all the data divided the number of data added. From the statement, we have 3 prices to be added and divided by 3. Therefore, the average is calculated as

($32 + $45 + $39) ÷ 3

7 0

3 years ago