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2 years ago

10

Two-thirds of the students in your class are boys. One eighth of the boys play soccer what fraction of the kids in your class ar

e boys who play soccer
Math period 4 — 9th Grade

1 answer:

andrew11 [14]2 years ago

7 0

Answer:

7 of the kids in your class play

Step-by-step explanation:

Hope this helps you :)

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Does the function f(x) = 2x^2− 6x + 9 have a minimum or a maximum? Identify its value.

exis [7]

Answer:

minimum value of function is $\frac{45}{8}$ .

Step-by-step explanation:

Given function represents a parabola.

Now, here coefficient of $x^{2}$ is positive , so the parabola will be facing upwards and thus the function will be having a minimum.

Now, as we know that minimum value of a parabolic function occurs at

x = $\frac{-b}{4a}$ .

Where , b represents the coefficient of x and a represents the coefficient of $x^{2}$ .

here, a = 2 , b = -6

Thus $\frac{-b}{4a}$ = $\frac{6}{8}$

= $\frac{3}{4}$

So, at x = $\frac{3}{4}$ minimum value will occur and which equals

y = 2× $\frac{9}{16}$ - $\frac{18}{4}$ + 9 = $\frac{45}{8}$ .

Thus , minimum value of function is $\frac{45}{8}$ .

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2 years ago

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

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3 years ago

I need help with this math

enot [183]

Answer:

question? haven't learn this yet but try asking desmos that app helps me a lot!

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20 Pour chacune des fonctions affines suivantes,

Ostrovityanka [42]

Answer:

2x+14-562-3838(789):

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BAKED GOODS Mary sells giant chocolate chip and peanut butter cookies for

mestny [16]

Answer:

(1.25c) + (1p) ≥ 25

c is the amount of chocolate chip cookies

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3 years ago