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2 years ago

6x(x-2y) Pls help me

Mathematics

1 answer:

lyudmila [28]2 years ago

6 0

Distribute 6x into (x - 2y):

= 6x^2 - 12xy

Hope this helps.

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64 ft of rope weighs 20 pounds 28 ft of rope weighs x pounds

castortr0y [4]

Answer

89.6

Step-by-step explanation:

Each foot of rope weighs 3.2 so then mutiplied 3.2 by 28 and got that

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3 years ago

Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

$\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C$

8 0

3 years ago

Can someone help me with this? Plz.<br><br> Solve the quadratic equation 2x^2-4x-1=0

Mila [183]

You have to use the quadratic formula to solve this. The zeros of this quadratic are 2 + sqrt2/2 and 2 - sqrt2/2, which in "real" numbers is 1.707 and .2928

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2 years ago

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ipn [44]

Answer:

To plot (4,2) start at the origin (0,0) and move right 4 units and up 2 units (4,2)

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3 years ago

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Korvikt [17]

Answer:

Step-by-step explanation:

In statistics and probability theory, the median is the value separating the higher half from the lower half of a data sample, a population or a probability distribution. For a data set, it may be thought of as the "middle" value. And the middle value in this problem is 4.

8 0

3 years ago

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