A uniform solid disk and a uniform hoop are placed side by side at the top of an incline of height h. If they are released from
1 answer:
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Answer:
-223.64684 J
Explanation:
F = Force that is applied to the crate = 68 N
s = Displacement of the crate = 3.5 m
= Angle between the force and displacement vector = (180-20)
Work done is given by
The work that Paige does on the crate is -223.64684 J
Answer:
If R₂=25.78 ohm, then R₁=10.58 ohm
If R₂=10.57 then R₁=25.79 ohm
Explanation:
R₁ = Resistance of first resistor
R₂ = Resistance of second resistor
V = Voltage of battery = 12 V
I = Current = 0.33 A (series)
I = Current = 1.6 A (parallel)
In series
In parallel
Solving the above quadratic equation
∴ If R₂=25.78 ohm, then R₁=10.58 ohm
If R₂=10.57 then R₁=25.79 ohm
Answer:
Accelerations of both the sides is 0.6125 , A moves downwards whereas B moves upwards.
=6.125 rad/
Tension on side A = 4.5 × g= 44.1 m/
Tension on side B= 2.0 × g= 19.6 m/
Explanation:
As both, the blocks A and B are attached due to the constraint they can only possess a single acceleration a.
Observe the figure attached, let the tension with Block A be and the tension attached with Block B be
.
Tensions will be only be due to the weight of the blocks as no other force is present.
= 4.5 × g= 44.1 m/
= 2.0 × g= 19.6 m/
Now, lets make a torque equation about the center of the wheel and find the alpha
×R-
×R= MI( Moment of Inertia of Wheel)× Alpha
where, R= Radius of the wheel=0.100m and
Alpha()= Angular acceleration of the wheel
MI of the wheel= 0.400 kg/
=6.125 rad/
Acceleration = R ×
= 0.1 * 6.125
=0.6125
Accelerations of both the sides is 0.6125 , A moves downwards whereas B moves upwards.
