Pretty sure its 97° i might be wrong
Yeah sure absolutely.
So the volume of a cone can be calculated with
![V= \pi r^{2} \frac{h}{3}](https://tex.z-dn.net/?f=V%3D%20%5Cpi%20r%5E%7B2%7D%20%5Cfrac%7Bh%7D%7B3%7D)
, you can substitute values into this like the following
![V = 3.14](https://tex.z-dn.net/?f=V%20%3D%203.14)
×
![12^{2}](https://tex.z-dn.net/?f=%2012%5E%7B2%7D%20)
<span>× </span>
![\frac{8}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B8%7D%7B3%7D%20)
, which is equal to
3x + 3 - x + (-7) > 6
2x - 4 > 6
2x > 6 + 4
2x > 10
x > 10/2
x > 5
Answer:
According to my very precise calculations, I've come to the conclusion that the answer is 1.
Answer:
![\huge\boxed{\sf \sqrt{-10} i}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Csf%20%5Csqrt%7B-10%7D%20i%7D)
Step-by-step explanation:
![\sf \sqrt{-10} \\\\\sqrt{10} * \sqrt{-1} \\\\We \ know \ that \ \sqrt{-1} = i\\\\= \sqrt{10} i\\\\= \sqrt{2*5 } i \\\\Since \ 2 \ and \ 5 \ are \ not \ perfect \ squares, they \ cannot \ be \ simplified\ further.\\\\= \sqrt{10} i\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%5Csqrt%7B-10%7D%20%5C%5C%5C%5C%5Csqrt%7B10%7D%20%2A%20%5Csqrt%7B-1%7D%20%5C%5C%5C%5CWe%20%5C%20know%20%5C%20that%20%5C%20%5Csqrt%7B-1%7D%20%3D%20i%5C%5C%5C%5C%3D%20%5Csqrt%7B10%7D%20i%5C%5C%5C%5C%3D%20%5Csqrt%7B2%2A5%20%7D%20i%20%5C%5C%5C%5CSince%20%5C%202%20%5C%20and%20%5C%205%20%5C%20are%20%5C%20not%20%5C%20perfect%20%5C%20squares%2C%20they%20%5C%20cannot%20%5C%20be%20%20%5C%20simplified%5C%20further.%5C%5C%5C%5C%3D%20%5Csqrt%7B10%7D%20i%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>