(1) The ball is in the air for <u>1.4 seconds.</u>
(2) The horizontal velocity of the ball as it rolls off the table is<u> 6.32 m/s.</u>
(3) The vertical velocity of the ball right before it hits the ground is <u>13.72 m/s.</u>
(4) The horizontal velocity of the ball right before it hits the ground is<u> 6.32 m/s.</u>
(5) The initial vertical velocity as soon as the ball comes of the cliff is <u>13.72 m/s.</u>
<h3>What is the time of motion of the ball?</h3>
The time of motion of the ball is calculated by applying the following equation.
t = √(2h/g)
where;
- h is the height of the cliff
- g is acceleration due to gravity
t = √(2h/g)
t = √(2 x 9.63 / 9.8)
t = 1.4 seconds
The horizontal velocity of the ball is calculated as follows;
v = d/t
where;
- d is the horizontal distance travelled by the ball = 8.85 m
v = 8.85 m / 1.4 s
v = 6.32 m/s
The vertical velocity of the ball before it hits the ground is calculated as;
vf = vi + gt
vf = 0 + 9.8 x 1.4
vf = 13.72 m/s
The horizontal velocity of the ball right before it hits the ground is calculated as;
the initial velocity of a projectile = final horizontal velocity
vxf = vxi = 6.32 m/s
The initial vertical velocity as soon as the ball comes off the cliff = final vertical velocity = 13.72 m/s
Learn more about horizontal velocity here: brainly.com/question/24949996
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<span>The jump from 1966 to 16347 is the largest one or simply we can say it is hard to lose the 3rd electron.Whereas, it is relatively easy to lose the first two electrons.
So there will be only 2 electrons in the outer most shell.
According to the information mentioned above we can conclude the </span><span>unknown element likely belongs to the second group.
</span><span>I2 = 1752 kj/mol</span>
Answer: 2 cm
Explanation:
Given , for a converging lens
Focal length : 
Height of object : 
Object distabce from lens : 
Using lens formula: 
, we get
, where v = image distance from the lens.
On solving aboive equation , we get
Formula of Magnification : 
, where h' is the height of image.
Put value of u, v and h in it , we get
Hence, the height of the image is 2 cm.
Answer:
F = 2 * 30 / 5 = 12 N to stop forward motion
F = 2 * 40 / 5 = 16 N to accelerate to 90 degrees
(12^2 + 16^2)^1.2 = 20 N average force applied
