Answer:
10.19 m
Explanation:
Water will rise to equalize the pressure inside and outside the tube.
The equation of pressure is given by

Where,
p = Pressure of air = 10⁵ N/m²
ρ = Density of water = 10³ kg/m³
g = Acceleration due to gravity = 9.81 m/s²
h = Height the water will rise

∴ The water will rise by 10.19 m.
Answer:
The magnitude of the force on the wire is 2.68 N.
Explanation:
Given that,
Length of the wire, L = 5 m
Magnetic field, B = 0.37 T
Angle between wire and the magnetic field, 
Current in the wire, I = 2.9 A
We need to find the magnitude of the force on the wire. The magnetic force in the wire is given by :

So, the magnitude of the force on the wire is 2.68 N. Hence, this is the required solution.
The magnitude of the unknown height of the projectile is determined as 16.1 m.
<h3>
Magnitude of the height</h3>
The magnitude of the height of the projectile is calculated as follows;
H = u²sin²θ/2g
H = (36.6² x (sin 29)²)/(2 x 9.8)
H = 16.1 m
Thus, the magnitude of the unknown height of the projectile is determined as 16.1 m.
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when approaching the front of an idling jet engine, the hazard area extends forward of the engine approximately 25 feet.
<h3>What impact, if any, would jet fuel and aviation gasoline have on a turbine engine?</h3>
Tetraethyl lead, which is present in gasoline, deposits itself on the turbine blades. Because jet fuel has a higher viscosity than aviation gasoline, it may retain impurities with greater ease.
Once the gasoline charge has been cleared, start the engine manually or with an electric starter while cutting the ignition and using the maximum throttle.
On the final approach, the aeroplane needs to be re-trimmed to account for the altered aerodynamic forces. A substantial nose-down tendency results from the airflow producing less lift on the wings and less downward force on the horizontal stabiliser due to the reduced power and slower velocity.
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Answer:
AM has longer wavelength
Explanation:
The relation between the wavelength and teh frequency is given by
v = f x λ
Where, f is the frequency and λ be the wavelength.
It shows that the wavelength is inversely proportional to the frequency.
So, higher the frequency, smaller be the wavelength.
So, FM has high frequency than AM, thus, FM has lower wavelength as compared to AM.