Answer:0.0909 kJ/K
Explanation:
Given
Temperature of hot Reservoir 
Temperature of cold Reservoir 
Heat of 100 kJ is transferred form hot reservoir to cold reservoir
Hot Reservoir is Rejecting heat therefore 
Heat is added to Reservoir therefore 
Entropy change for system
As entropy change is Positive therefore entropy Principle is satisfied
The fundamental frequency of this open-open pipe is 8.82 Hz
The quantity of waves that pass a set location in a predetermined period of time is known as frequency. Frequency is the number of full cycles per second in the alternating current direction for an oscillating or fluctuating current. The hertz, also known as Hz, is the accepted unit of frequency.
The temporal rate of change observed in oscillatory and periodic phenomena, such as mechanical vibrations, audio signals (sound), radio waves, and light, is specified by the frequency, an essential parameter in science and engineering.
Assume vs = 344 m/s
f1 = vs/2L
= 344 m/s/ 2∙64 ft/(3.281 ft/m)
= 8.82 Hz
To know more about Frequency refer:
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This question is not complete.
The complete question is as follows:
One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a space station that spins about its center at a constant rate. This creates “artificial gravity” at the outside rim of the station. (a) If the diameter of the space station is 800 m, how many revolutions per minute are needed for the “artificial gravity” acceleration to be 9.80m/s2?
Explanation:
a. Using the expression;
T = 2π√R/g
where R = radius of the space = diameter/2
R = 800/2 = 400m
g= acceleration due to gravity = 9.8m/s^2
1/T = number of revolutions per second
T = 2π√R/g
T = 2 x 3.14 x √400/9.8
T = 6.28 x 6.39 = 40.13
1/T = 1/40.13 = 0.025 x 60 = 1.5 revolution/minute
The efficiency of the scissor is 200%.
<u>Explanation:</u>
Efficiency is defined as the ratio of output of any instrument or device or machine to the input supplied to it. So the greater the output the greater will be the efficiency of the device.
As here the work done by us on the system is said to be 10 J so this will be equal to the input work done on the system. And the work done by the system i.e., the scissor is 20 J, so this will be the output work.
So, the efficiency is the ratio of output to input as shown below.
Efficiency = 
= 200
So, the efficiency of the scissor is 200%.
