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IRINA_888 [86]
3 years ago
6

How do different lense types connect to helping locate sharks through mechanical radio waves?​

Physics
1 answer:
Gnom [1K]3 years ago
5 0

Answer:

I am not quite sure, but maybe you can find something from these websites

The second one to me is the best. Sorry if it wasn't what you needed. :(

Explanation:

https://phys.org/news/2012-11-metamaterial-lens-focuses-radio-device.html

https://animals.howstuffworks.com/fish/sharks/shark-yummy-hum1.htm

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A 15.0 m long plane is inclined at 30.0 degrees. If the coefficient of friction is 0.426, what force is required to move a 40.0
FromTheMoon [43]

consider the motion of the mass parallel to the incline

v₀ = initial velocity at the bottom of incline = 0 m/s

v = final velocity at the top of incline = 8.00 m/s

a = acceleration

d = displacement = L = length of incline = 15 m

using the equation

v² = v²₀ + 2 a d

8² = 0² + 2 a (15)

64 = 30 a

a = 64/30

a = 2.13 m/s²

F = applied force

from the force diagram, perpendicular to incline , force equation is given as

N = mg Cos30

μ = Coefficient of friction = 0.426

frictional force acting on the mass is given as

f = μ N

f = μ mg Cos30

parallel to incline , force equation is given as

F - f - mg Sin30 = ma

F - μ mg Cos30 - mg Sin30 = ma

inserting the values

F - (0.426 x 40 x 9.8) Cos30 - (40 x 9.8) Sin30 = 40 (2.13)

F = 425.82 N

4 0
3 years ago
A bullet is at rest. It travels a distance of 0.34m in a time of 0.0095 seconds. Calculate its acceleration.
tamaranim1 [39]

Answer:

7.5 × 10^3 m/s^2

Explanation:

use the formula that does not have v in it to solve for acceleration.

7 0
3 years ago
A light ray traveling through medium 1, index of refraction n1n1n_1 = 1.75, reaches the interface between medium 1 and medium 2,
horrorfan [7]

Answer:

θ₁ = 35.32°

Explanation:

given,

refractive index of medium 1 = n₁ = 1.75

refractive index of medium 2 = n₂ = 1.24

condition to describe the refracted angle

 \theta_{refracted} + \theta_{reflected}=90^0

 \theta_2 = 90^0-\theta_1...(1)

Using Snell's Law

   n₁ sin θ₁ = n₂ sin θ₂

θ₁ , θ₂ is the angle of incidence and refractive index

n₁. n₂ is the refractive index medium 1 and medium 2

   1.75 x  sin θ₁ = 1.24 x sin θ₂

From equation (1)

   1.75 x  sin θ₁ = 1.24 x sin (90-θ₁)

   1.75 sin θ₁ = 1.24 cos θ₁

      tan θ₁ = 0.708

         θ₁ = 35.32°

Hence, angle of incidence is equal to θ₁ = 35.32°

7 0
3 years ago
A maser is a laser-type device that produces electromagnetic waves with frequencies in the microwave and radio-wave bands of the
rusak2 [61]

Answers:

a) T=7.04(10)^{-10} s

b) 5.11(10)^{12} cycles

c) 2.06(10)^{26} cycles

d) 46000 s

Explanation:

<h2>a) Time for one cycle of the radio wave</h2>

We know the maser radiowave has a frequency f of 1,420,405,751.786 cycles/s

In addition we know there is an inverse relation between frequency and time T:

f=\frac{1}{T} (1)

Isolating  T: T=\frac{1}{f} (2)

T=\frac{1}{1,420,405,751.786 cycles/s} (3)

T=7.04(10)^{-10} s (4) This is the time for 1 cycle

<h2>b) Cycles that occur in 1 h</h2>

If 1h=3600s and we already know the amount of cycles per second 1,420,405,751.786 cycles/s, then:

1,420,405,751.786 \frac{cycles}{s}(3600s)=5.11(10)^{12} cycles This is the number of cycles in an hour

<h2>c) How many cycles would have occurred during the age of the earth, which is estimated to be 4.6(10)^{9} years?</h2>

Firstly, we have to convert this from years to seconds:

4.6(10)^{9} years \frac{365 days}{1 year} \frac{24 h}{1 day} \frac{3600 s}{1 h}=1.45(10)^{17} s

Now we have to multiply this value for the frequency of the maser radiowave:

1,420,405,751.786 cycles/s (1.45(10)^{17} s)=2.06(10)^{26} cycles This is the number of cycles in the age of the Earth

<h2>d) By how many seconds would a hydrogen maser clock be off after a time interval equal to the age of the earth?</h2>

If we have 1 second out for every 100,000 years, then:

4.6(10)^{9} years \frac{1 s}{100,000 years}=46000 s

This means the maser would be 46000 s off after a time interval equal to the age of the earth

7 0
3 years ago
You have a mass of 95 kg.<br> a. What is your weight on Earth?
svp [43]

Answer:

931.63N

Hope this helps :D

8 0
3 years ago
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