All categories

3 years ago

How do different lense types connect to helping locate sharks through mechanical radio waves?

Physics

1 answer:

Gnom [1K]3 years ago

5 0

Answer:

I am not quite sure, but maybe you can find something from these websites

The second one to me is the best. Sorry if it wasn't what you needed. :(

Explanation:

https://phys.org/news/2012-11-metamaterial-lens-focuses-radio-device.html

https://animals.howstuffworks.com/fish/sharks/shark-yummy-hum1.htm

You might be interested in

How can you prove the mechanical nature of sound by a simple experiment

Kruka [31]

Answer:

That is, mechanical waves cannot travel through a vacuum. This feature of mechanical waves is often demonstrated in a Physics class. A ringing bell is placed in a jar and air inside the jar is evacuated. Once air is removed from the jar, the sound of the ringing bell can no longer be heard.

6 0

3 years ago

Use the values provided to calculate the initial voltage

EleoNora [17]

Answer: V1= 360 V

Explanation:

7 0

3 years ago

Read 2 more answers

Which person is weightless?

ahrayia [7]

Answer: Option (b) is the correct answer.

Explanation:

The force of gravity acting on an object helps in determining the weight of an object. But a place where there will be no gravity or have zero gravitational pull then it means the person will be weightless.

For example, force of gravity on moon is zero which means any object or person on moon will be weightless.

On the other hand, when a child is in the air as she plays on a trampoline then it means gravitational pull form the earth is acting on it. So, it will definitely has some weight.

Similarly, a scuba diver exploring a deep-sea wreck is under the ground where there will be force of gravity. Hence, it will also have some weight.

Thus, we can conclude that an astronaut on the Moon is the person who is weightless.

7 0

3 years ago

mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan

Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, $v_e$ , for the planet is $v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }$

Where;

$v_e$ = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, $M_E$

r = The radius of the planet = 3 × The radius of Earth, $R_E$

The escape velocity for Earth, $v_e_E$ , is therefore given as follows;

$v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }$

$\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } = \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E$

$v_e$ = 16 × $v_e_E$

Given that the escape velocity for Earth, $v_e_E$ ≈ 11,186 m/s, we have;

The escape velocity on the planet = $v_e$ ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0

3 years ago

The default unit of rotational speed is 'radians per second' or 'rad/s'. If a someone sits at the edge of a 5m radius carousel a

Blizzard [7]

The rotational speed of the person is 0.4 rad/s.

<h3>Rotational speed (rad/s)</h3>

The rotational speed of the person in radian per second is calculated as follows;

v = ωr

where;

v is linear speed in m/s
r is radius in meters
ω is speed in rad/s

ω = v/r

ω = 2/5

ω = 0.4 rad/s

Thus, the rotational speed of the person is 0.4 rad/s.

Learn more about rotational speed here: brainly.com/question/6860269

7 0

3 years ago

How do different lense types connect to helping locate sharks through mechanical radio waves?​

How do different lense types connect to helping locate sharks through mechanical radio waves?