If we consider the reaction CH₃O⁻ + H₂O ⇌ CH₃OH + OH⁻ in the forward direction, the base in the reaction is CH₃O⁻
A compound can be acidic, basic or neutral in nature. Basicity of the compound is determined when it either releases hydroxide ions, donates electrons or else accepts the protons from a compound.
In the reaction CH₃O⁻ + H₂O ⇌ CH₃OH + OH⁻:
CH₃O⁻ accepts proton or [H+] ion to become CH₃OH. Thus, CH₃O⁻ is the base in the reaction
H₂O donate [H+] ion or proton, therefore H2O change into OH-. Thus, H₂O is an acid in the reaction.
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Answer: The given statement is True.
Explanation:
An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal.
A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.
Thus the given statement is True.
It absorbed 41,600 joules.
Explanation:
If the sample of sucrose burnt in the calorimeter releases 41600Joules of heat, then the water in the calorimeter will absorb 41600J.
The heat lost by burning the sucrose in the calorimeter is also the heat gained by the water therein.
A calorimeter is a device by prevents heat loss to the environment in any form.
It is specially designed to minimize heat loss by conduction, convection radiation.
Therefore, since no heat is lost, the heat released by burning the sucrose is used in heating the water there.
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The thing that governs whether a reaction is exothermic is the energy given out / used up to break / form the bonds in the reaction.
<span>When two substances react, the bonds in those substances first break up, releasing energy, before re-forming in a different way, taking in energy. The nature of the bonds that are broken up and reformed determines whether more energy is given out (exothermic) or taken in (endothermic)</span>
