Given :
A gas with a volume of 2 L at 25°C is placed into a container that is 4 L.
To Find :
The new temperature of the gas.
Solution :
Since, their is no information regarding pressure. We will assume that pressure is constant.
Now, we know when at constant pressure, volume is directly proportional to volume.
Therefore, the new temperature of the gas is 596 - 273 K = 323 K.
This is an incomplete question, here is a complete question.
If the initial concentration of NOBr is 0.0440 M, the concentration of NOBr after 9.0 seconds is ________.
The reaction
It is a second-order reaction with a rate constant of 0.80 M⁻¹s⁻¹ at 11 °C.
Answer : The concentration of after 9.0 seconds is, 0.00734 M
Explanation :
The integrated rate law equation for second order reaction follows:
where,
k = rate constant = 0.80 M⁻¹s⁻¹
t = time taken = 142 second
[A] = concentration of substance after time 't' = ?
= Initial concentration = 0.0440 M
Putting values in above equation, we get:
Hence, the concentration of after 9.0 seconds is, 0.00734 M