Answer:
If there is some sort of error
Explanation:
If there is an error that is causing problems for clients that needs to be worked out still, rolling back allows customers to still do whatever they need while you look for a solution in the new version.
I believe it is the first one, i did some research for this question
Answer:
The correct answer is:
C. ndx = 0;
while (ndx < 3) {
ar[ndx] = 0;
ndx++;
}
Explanation:
The declaration given is:
int ar[3];
This means the array consists of three locations and is named as ar.
We know that the indexes are used to address the locations of an array and the index starts from 0 and goes upto to 1 less than the size of the array which means the indexes of array of 3 elements will start from 0 and end at 2.
Now in the given options we are using ndx variable to run the while loop.
So the code to assign zero to all elements of array will be
ndx = 0;
while(ndx<3)
{
ar[ndx] = 0;
ndx++;
}
Hence, the correct answer is:
C. ndx = 0;
while (ndx < 3) {
ar[ndx] = 0;
ndx++;
}
It D because I hade this too so it is D
Answer:
The answer is "Option B, C, and F".
Explanation:
In the For-each loop, it is used for traversing items in a sequence is the control flow expression. It typically required a loop becomes referred to it as an enhanced loop for iterating its array as well as the collection elements. This loop is a version shortcut that skips the need for the hasNext() method to get iterator and the loop and over an iterator, and the incorrect choice can be determined as follows:
- In choice A, it is wrong because it can't reverse the array element.
- In choice D, it is wrong because it can't determine the array of positive.
- In choice E, it is wrong because it can't determine an array of the sting in alphabetical order.