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Solnce55 [7]
3 years ago
7

Given the reaction: __hg2+ + __ag0 → __hg0 + __ag1+when the equation is completely balanced using the smallest whole-number coef

ficients, the coefficient of hg will be
Chemistry
1 answer:
Tju [1.3M]3 years ago
4 0
Answer is: <span>the coefficient of Hg will be 1.

Balanced chemical reaction: H</span>g²⁺ + 2Ag⁰ → Hg⁰ + 2Ag⁺.
Oxidation half reaction: Ag⁰ → Ag⁺ + e⁻/×2; 2Ag⁰ → 2Ag⁺ + 2e⁻
Reduction half reaction: Hg²⁺ + 2e⁻ → Hg⁰.
Mercury cation gain two electrons and become mercury metal with neutral charge (reduction), silver lost electrons and become silver cation (oxidation).
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Whenever a continuous bell alarm sounds in the Chemistry building:
deff fn [24]

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C

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4 0
3 years ago
The first-order rate constant for the reaction of methyl chloride (CH3Cl) with water to produce methanol (CH3OH) and hydrochlori
Dvinal [7]

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K(48.5°C) = 1.017 E-8 s-1

Explanation:

  • CH3Cl + H2O → CH3OH + HCl

at T1 = 25°C (298 K) ⇒ K1 = 3.32 E-10 s-1

at T2 = 48.5°C (321.5 K) ⇒ K2 = ?

Arrhenius eq:

  • K(T) = A e∧(-Ea/RT)
  • Ln K = Ln(A) - [(Ea/R)(1/T)]

∴ A: frecuency factor

∴ R = 8.314 E-3 KJ/K.mol

⇒ Ln K1 = Ln(A) - [Ea/R)*(1/T1)]..........(1)

⇒ Ln K2 = Ln(A) - [(Ea/R)*(1/T2)].............(2)

(1)/(2):

⇒ Ln (K1/K2) = (Ea/R)* (1/T2-1/T1)

⇒ Ln (K1/K2) = (116 KJ/mol/8.3134 E-3 KJ/K.mol)*(1/321.5 K - 1/298 K)

⇒ Ln (K1/K2) = (13952.37 K)*(- 2.453 E-4 K-1)

⇒ Ln (K1/K2) = - 3.422

⇒ K1/K2 = e∧(-3.422)

⇒ (3.32 E-10 s-1)/K2 = 0.0326

⇒ K2 = (3.32 E-10 s-1)/0.0326

⇒ K2 = 1.017 E-8 s-1

7 0
3 years ago
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